You use kinematics for this problem. You know your Vo (initial velocity) is 130 km/h or 2166.67 m/s. The Vf (final velocity) is 0 and time is .14 seconds.
You can use the equation: Vf=Vo+at and plug the numbers in
0=(2166.67)+a(.14)
a=15476 m/s or 928.57 km/h
Answer:
The volume flow rate of the pipe is 1.41 x 10⁻³ m³/s
Explanation:
Given;
velocity of the fluid, v = 2.0 m/s
diameter of the pipe, d = 3.0 cm = 0.03 m
The volume flow rate is given by;
Q = Av
Where;
A is the area of the pipe
v is the velocity of the fluid
circular surface Area of the pipe is given by;
A = ¹/₄ πd²
A = ¹/₄ π(0.03)² = 7.07 x 10⁻⁴ m²
Q = (7.07 x 10⁻⁴)(2)
Q = 1.41 x 10⁻³ m³/s
Therefore, the volume flow rate of the pipe is 1.41 x 10⁻³ m³/s
Answer:
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Machine
Subject: Science
Home Grade 9 Science Machine Machine
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Syllabus
Measurement
Force
Machine
Machine
Types of Simple Machine
Moment
Work Energy and Power
Sound
Light
Electricity and Magnetism
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Overview
Simple machine helps us by magnifying force, accelerating work and by changing the direction of force. This notes gives us the information about machine, its importance, mechanical advantage, velocity ratio.
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Machine
We use various tools to perform different types of work in our daily life. The tools or simple devices used for making our work easier, faster and more convenient are simple machines.
Those tools or devices which make our work easier and convenient in the direction of the force is called simple machine.
Purpose of using simple machine
Simple machines are used to make our work easier in the following ways:
By multiplying force.
By changing the directions of force.
By transferring force from one point to another.
By increasing the rate of doing work.
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Answer:
Explanation:
distance travelled s = 10 cm
speed v = 1.4 x 10⁶ m /s
v² = u² + 2as
u = 0
v² = 2as
( 1.4 x 10⁶ )² = 2 x a x .10
a = 9.8 x 10¹² m /s²
force on proton = mass x acceleration
= 1.67 x 10⁻²⁷ x 9.8 x 10¹²
= 16.366 x 10⁻¹⁵ N .
If magnitude of electric field be E
force on proton
= E x charge on proton
= E x 1.6 x 10⁻¹⁹
E x 1.6 x 10⁻¹⁹ = 16.366 x 10⁻¹⁵
E = 10.22 x 10⁴ N/C
The direction of electric field will be positive x - direction .
b )
Speed of proton = 1.4 x 10⁶ m /s .
The collision between a photon or a bundle of energy and an electron is known as the Compton Effect in which there is a transference of energy and momentum by the photon to the recoiling electron. It must be noted that both energy and momentum are being conserved during this elastic collision. After such phenomena, the photon acquires energy (represented by hf/) and the electron also has acquired a kinetic energy (represented by K).
