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Rudik [331]
3 years ago
5

One number is 8 times a first number. A third number is 100 more than the first number. If the sum of the three is 690, find the

numbers.
Mathematics
1 answer:
mezya [45]3 years ago
6 0
<h3>Given</h3>

Three numbers are n, 8n, and (100+n).

Their total is 690.

<h3>Find</h3>

the three numbers

<h3>Solution</h3>

n + 8n + (n+100) = 690

10n + 100 = 690 . . . . . . . simplify

10n = 590 . . . . . . . . . . . . subtract 100

n = 59

8n = 472

n +100 = 159

The three numbers are 59, 472, and 159.

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A line passes through the points (1.4) and (2, 2). What is the equation of this line?
emmasim [6.3K]

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y = - 2x + 6

Step-by-step explanation:

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Step by Step Explanation:

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For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(10, 9) = 90. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 10 × 9 = 90. In the following intermediate step, cancel by a common factor of 2 gives 41/

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[297÷3 + { 4 × 3 ( 20 – 36 ÷ 5 – 2)}]​
maw [93]

Here is the answer to your problem:

<h3><u>https://brainly.in/question/10886862</u></h3>

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