Question

One number is 8 times a first number. A third number is 100 more than the first number. If the sum of the three is 690, find the numbers.

Answer 1

Given

Three numbers are n, 8n, and (100+n).

Their total is 690.

Find

the three numbers

Solution

n + 8n + (n+100) = 690

10n + 100 = 690 . . . . . . . simplify

10n = 590 . . . . . . . . . . . . subtract 100

n = 59

8n = 472

n +100 = 159

The three numbers are 59, 472, and 159.