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Rudik [331]
3 years ago
5

One number is 8 times a first number. A third number is 100 more than the first number. If the sum of the three is 690, find the

numbers.
Mathematics
1 answer:
mezya [45]3 years ago
6 0
<h3>Given</h3>

Three numbers are n, 8n, and (100+n).

Their total is 690.

<h3>Find</h3>

the three numbers

<h3>Solution</h3>

n + 8n + (n+100) = 690

10n + 100 = 690 . . . . . . . simplify

10n = 590 . . . . . . . . . . . . subtract 100

n = 59

8n = 472

n +100 = 159

The three numbers are 59, 472, and 159.

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We are given two equations;

-6x + 3y = 6  ---(eq 1)

x² + y = 10 ---(eq 2)

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Let us make y the subject in eq 2 to get;

y = 10 - x²  --(eq 3)

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rearranging gives;

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Using online quadratic equation <em>solver</em>, we have;

x = -4 and x = 2

Putting x = -4 into eq 3 gives;

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Putting x = 2 into eq 3 gives;

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y = 10 - 4

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Comparing with (a, b) and (c,d), we have;

a = -4

b = -6

c = 2

d = 6

Read more at; brainly.com/question/15165519

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