9514 1404 393
Answer:
Step-by-step explanation:
For this to have infinitely many solutions, the left side and right side must simplify to the same expression. The left side is already simplified, so we need to find the right numbers for the right side.
Coefficient of x:
7x = __x + 3x
4x = __x . . . . . . subtract 3x; next divide by x
4 = __ . . . . . the required x-coefficient is 4
Constant term:
-8 = 8 -__
-16 = -__ . . . . . subtract 8
16 = __ . . . . . . multiply by -1
__
The numbers that go in the boxes are 4 and 16.
Answer:
SB or ? = 9
Step-by-step explanation:
Since the two triangles are similar.
((18 + 6) / 6) = 24 / 6 = <u>4</u>
[Scale factor between ∆BCU and ∆SUT]
SB or ? = 12 – 12/<u>4</u> = 12 – 3 = 9
1 gallon is 3.78 L
100 sq feet needs 1 L
800 sq feet needs x
100/800 = 1/x
100x = 800
x = 800/100
x = 8 L
If you use the fact that 4 L = 1 gallon then you need 2 gallons of paint. I you use the more accurate 3.78 L then
1 gallon = 3.78 L
x gallon = 8 L
3.78 x = 8*1
x = 8/3.78
x = 2.12 gallons.
I guess you could say that 1 gallon and 1 L would do you.
Answer:
At a combined speed of 6 in/min, it takes us 24 mins to clean the wall
Step-by-step explanation:
Since the question did not provide the speed with which each student cleans, we can make assumptions. This is so that we can solve the question before us
Assuming student 1 cleans at a speed of 2 inches per minute, student 2 cleans at a speed of 2½ inches per minute & student 3 cleans at a speed of 1½ inches per minute.
Let's list the parameters we have:
Height of wall (h) = 12 ft, Speed (student 1) = 2 in/min, Speed (student 2) = 2½ in/min, Speed (student 3) = 1½ in/min
Speed of cleaning wall = Height of wall ÷ Time to clean wall
Time to clean wall (t) = Height of wall ÷ Speed of cleaning wall
since students 1, 2 and 3 are working together, we will add their speed together; v = (2 + 2½ + 1½) = 6 in/min
1 ft = 12 in
Time (t) = h ÷ v = (12 * 12) ÷ 6 = 144 ÷ 6
Time (t) = 24 mins
