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777dan777 [17]
3 years ago
8

Write an equation for the given points The points (20, -136) and (-35,-92) both lie on the line

Mathematics
1 answer:
ale4655 [162]3 years ago
3 0

Answer:

y = (8/11)x + (740/11)b

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Use the disruptive property to simplify the expression 4(2x-4)
KIM [24]

Answer:

C.8x - 16

Step-by-step explanation:

multiple 4 with 2x = 8x,

then multiple 4 with -4 = -16

add 8x and -16 the answer is 8x - 16

5 0
3 years ago
A company that produces fine crystal knows from experience that 17% of its goblets have cosmetic flaws and must be classified as
Alex73 [517]

Answer:

0.3891 = 38.91% probability that only one is a second

Step-by-step explanation:

For each globet, there are only two possible outcoes. Either they have cosmetic flaws, or they do not. The probability of a goblet having a cosmetic flaw is independent of other globets. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

17% of its goblets have cosmetic flaws and must be classified as "seconds."

This means that p = 0.17

Among seven randomly selected goblets, how likely is it that only one is a second

This is P(X = 1) when n = 7. So

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 1) = C_{7,1}.(0.17)^{1}.(0.83)^{6} = 0.3891

0.3891 = 38.91% probability that only one is a second

7 0
3 years ago
Please help!! One question. Multiple choice.
Mamont248 [21]
The answer to your question is A. 359.5
6 0
3 years ago
Simplify and evaluate without a calculator. 3*(m-4)-n*(m-4) if m=5 and n=3
Katarina [22]

Answer:

0

Step-by-step explanation:

3*(m-4)-n*(m-4)   m = 5, n = 3

3*(5-4)-3*(5-4)

3*(1)-3*(1)

3-3

0

6 0
2 years ago
Read 2 more answers
Students planted 4(2x+3y) amount of trees on saturday and then 3(5x+4) amount of trees on Sunday. What is the total amount of tr
algol [13]
We have to add the amounts:

4(2x+3y) + 3(5x+4)

First, though, we have to distribute:

4*2x + 4*3y + 3*5x + 3*4
8x + 12y + 15x + 12

Now we just need to simplify:

23x + 12y + 12

The  students planted 23x + 12y + 12 trees total.
7 0
3 years ago
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