Trying to get my grade up
2 answers:
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Hello,
y=2^(-x)
y=2^(2x)+3
==>2^(2x)+3=1/2^x
==>2^(3x)+3*2^x-1=0 (1)
Let's assume u=2^x
(1)==>u^3+3*u-1=0
which as 3 roots
u=0.322185354626 or
u = -0.161092677313 + i1.754380959784 or
u = -0.161092677313 - i1.754380959784.
Let's take the real solution
0.322185354626=2^x
==>x=ln(0.322185354626) / ln(2)
x=-1,6340371790199...
an other way is
f(x)=2^(3x)+3*2^x-1
f(-2)=1/64+3/4-1=-15/64 <0
f(-1)=1/8+1-1=1/8>0
==> there is a solution betheen -2<x<-1
y=2^(-x)
y=2^(2x)+3
==>2^(2x)+3=1/2^x
==>2^(3x)+3*2^x-1=0 (1)
Let's assume u=2^x
(1)==>u^3+3*u-1=0
which as 3 roots
u=0.322185354626 or
u = -0.161092677313 + i1.754380959784 or
u = -0.161092677313 - i1.754380959784.
Let's take the real solution
0.322185354626=2^x
==>x=ln(0.322185354626) / ln(2)
x=-1,6340371790199...
an other way is
f(x)=2^(3x)+3*2^x-1
f(-2)=1/64+3/4-1=-15/64 <0
f(-1)=1/8+1-1=1/8>0
==> there is a solution betheen -2<x<-1
The correct answer is: True
Explanation:
1.
(Straightforward)
2.
(log to base of itself is always 1)
3.
(Using log power property)
Hence the correct option is True.
Explanation:
1.
2.
3.
Hence the correct option is True.
Answer:
<em>d = 3</em>
Step-by-step explanation:
Coordinate Plane
The image provided shows the four points given:
A=(2, 1), B=(5, 1), C=(7,2), D=(4,2).
It can be clearly seen the length of CD is just the difference of their x-coordinates:
CD = 7 - 4 = 3
We can also use the formula of the distance.
Given two points C(x,y) and D(w,z), the distance between them is:
d = 3
