This is a difference of perfect squares which is of the form:
(a^2-b^2)
And which always factors to:
(a-b)(a+b)
In this case:
(5x-8)(5x+8)
How to solve your problem
9−4+3
9x−4+3x9x-4+3x9x−4+3x
Simplify
1
Combine like terms
9−4+3
9x−4+3x{\color{#c92786}{9x}}-4+{\color{#c92786}{3x}}9x−4+3x
12−4
12x−4{\color{#c92786}{12x}}-412x−4
Solution
12−4
SO D
Let no be x
Acc to ques
X + 2(1/x) = 3
X + 2/x = 3
X^2 + 2 = 3x
X^2 - 3x + 2 = 0
X^2 - x - 2x + 2 = 0
X (x-1) - 2 (x-1) = 0
(x-2) (x-1) = 0
X= 2 or x =1
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The answer would be 2(6x+5+2y) you can figure this out through the distributive property. 2(6x)=12x 2(5)=10 and 2(2y)= 4y this would reult in giving you the equation 12x+10+4y
Answer:
h=3.24
Step-by-step explanation:
