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2 years ago

ABC is translated 2 units right and 1 unit down. What is the new location of point C?

Mathematics

2 answers:

Bogdan [553]2 years ago

8 0

Answer:

(4,-8)

Step-by-step explanation

hope it helps

LenKa [72]2 years ago

3 0

Answer:

it's (4,-6)

Step-by-step explanation:

the first answer given by the other user is incorrect.

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(t+9)20=140 what is t

GarryVolchara [31]

Answer:

t=-2

Step-by-step explanation:

(t+9)20=140

Distribute the 20

20t +180 = 140

Subtract 180 from each side

20t +180-180 = 140-180

20t = -40

Divide by 20

20t/20 = -40/20

t=-2

8 0

2 years ago

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Can someone help me please?

taurus [48]

Answer:

437.4 meters squared

Step-by-step explanation:

7.2*4.5=32.4=b

3*4.5=13.5=h

b*h=a

32.4*13.5=437.4m^2

3 0

3 years ago

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Find the limit

Lana71 [14]

Step-by-step explanation:

<h3>Appropriate Question :-</h3>

Find the limit

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

On substituting directly x = 1, we get,

$\rm \: = \: \sf \dfrac{1-2}{1 - 1}-\dfrac{1}{1 - 3 + 2}$

$\rm \: = \sf \: \: - \infty \: - \: \infty$

which is indeterminant form.

Consider again,

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

can be rewritten as

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 3x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 2x - x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( x(x - 2) - 1(x - 2))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ {(x - 2)}^{2} - 1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 2 - 1)(x - 2 + 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)(x - 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)}{x(x - 2)}\right]$

$\rm \: = \: \sf \: \dfrac{1 - 3}{1 \times (1 - 2)}$

$\rm \: = \: \sf \: \dfrac{ - 2}{ - 1}$

$\rm \: = \: \sf \boxed{2}$

Hence,

$\rm\implies \:\boxed{ \rm{ \:\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right] = 2 \: }}$

$\rule{190pt}{2pt}$

7 0

2 years ago

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The density curve below represents the number of hours that Mrs. Schultz's students spent studying for

Brut [27]

Answer:

the mean of the study times is greater than the median

Step-by-step explanation:

8 0

3 years ago

Find the slope of the line that passes through (1, 8) and (10, 1).

leonid [27]

Answer:

$m = \frac{1 - 8}{10 - 1} = - \frac{ 7}{9} \\$

Slope(gradient)=

$-\frac{7}{9}$

Good luck!

Intelligent Muslim,

From Uzbekistan.

8 0

3 years ago

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