The pattern of a linear function, is the following:
y = mx + b
Where m is always the slope.
m in this case is -4, hence
The correct answer for your question is -4.
Answer:
Twelve pence made a shilling
I hope this is the ans
Just plot the points on the graph.
2. You know since the graph is a straight line, the ratios are proportional and therefore equivalent
Answer: 11.5%
Explanation:Since 1 minute = 60 seconds, we multiply 12 minutes by 60 so that 12 minutes = 720 seconds. Thus, we're looking for a probability that the auditor will spend more than 720 seconds.
Now, we get the z-score for 720 seconds by the following formula:
![\text{z-score} = \frac{x - \mu}{\sigma}](https://tex.z-dn.net/?f=%5Ctext%7Bz-score%7D%20%3D%20%20%5Cfrac%7Bx%20-%20%5Cmu%7D%7B%5Csigma%7D%20)
where
![t = \text{time for the auditor to finish his work } = 720 \text{ seconds} \\ \mu = \text{average time for the auditor to finish his work } = 600 \text{ seconds} \\ \sigma = \text{standard deviation } = 100 \text{ seconds}](https://tex.z-dn.net/?f=t%20%3D%20%5Ctext%7Btime%20for%20the%20auditor%20to%20finish%20his%20work%20%7D%20%3D%20720%20%5Ctext%7B%20seconds%7D%0A%5C%5C%20%5Cmu%20%3D%20%5Ctext%7Baverage%20time%20for%20the%20auditor%20to%20finish%20his%20work%20%7D%20%3D%20600%20%5Ctext%7B%20seconds%7D%0A%5C%5C%20%5Csigma%20%3D%20%5Ctext%7Bstandard%20deviation%20%7D%20%3D%20100%20%5Ctext%7B%20seconds%7D)
So, the z-score of 720 seconds is given by:
![\text{z-score} = \frac{x - \mu}{\sigma} \\ \\ \text{z-score} = \frac{720 - 600}{100} \\ \\ \boxed{\text{z-score} = 1.2}](https://tex.z-dn.net/?f=%5Ctext%7Bz-score%7D%20%3D%20%5Cfrac%7Bx%20-%20%5Cmu%7D%7B%5Csigma%7D%0A%5C%5C%0A%5C%5C%20%5Ctext%7Bz-score%7D%20%3D%20%5Cfrac%7B720%20-%20600%7D%7B100%7D%0A%5C%5C%0A%5C%5C%20%5Cboxed%7B%5Ctext%7Bz-score%7D%20%3D%201.2%7D)
Let
t = time for the auditor to finish his work
z = z-score of time t
Since the time is normally distributed, the probability for t > 720 is the same as the probability for z > 1.2. In terms of equation:
![P(t \ \textgreater \ 720) \\ = P(z \ \textgreater \ 1.2) \\ = 1 - P(z \leq 1.2) \\ = 1 - 0.885 \\ \boxed{P(t \ \textgreater \ 720) = 0.115}](https://tex.z-dn.net/?f=P%28t%20%5C%20%5Ctextgreater%20%5C%20%20720%29%20%0A%5C%5C%20%3D%20P%28z%20%5C%20%5Ctextgreater%20%5C%20%201.2%29%0A%5C%5C%20%3D%201%20-%20P%28z%20%5Cleq%201.2%29%0A%5C%5C%20%3D%201%20-%200.885%0A%5C%5C%20%20%5Cboxed%7BP%28t%20%5C%20%5Ctextgreater%20%5C%20%20720%29%20%20%3D%200.115%7D)
Hence, there is
11.5% chance that the auditor will spend more than 12 minutes in an invoice.
The answer is 10/3. Because you have 3 wholes and 1/3 so, 3x3 is 9 and you still have the extra 1 so 9+1=10 therefore your answer would be 10/3