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Licemer1 [7]
3 years ago
13

What is the pre-image of vertex A' if the rule that created the image is ry-axis(x, y) → (–x, y)? A(–4, 2) A(–2, –4) A(2, 4) A(4

, –2)
Mathematics
2 answers:
aev [14]3 years ago
8 0

do you have a picture

mote1985 [20]3 years ago
3 0

the answer is A on eng.

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Lines k and p are perpendicular, neither is vertical and p passes through the origin. Which is greater? A. The product of the sl
AlladinOne [14]
What do we know about those two lines?

They are perpendicular, meaning they have the same slope.
We know the slope of both is not zero (neither is vertical).
Therefore either
1) Both slopes are positive and therefore the product is positive
2) Both slopes are negative and therefore the product is positive (minus by a minus is a plus)

For the y intercepts, we know that the line P passes through the origin.
Therefore its Y intercept is zero.
[draw it if this is not obvious and ask where does it cross the y axis]
Therefore the Y intercept of line K and line P is zero.
[anything multiplied by a zero is a zero]

So we know that the product of slopes is positive, and we know that the product of Y intercepts is zero.
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Answer A
4 0
3 years ago
Which angles are pairs of corresponding angles? Check all that apply
AleksAgata [21]

Answer:

B and D people. Your welcome.

Step-by-step explanation:

6 0
3 years ago
A metallurgist has one alloy containing 34% copper another containing 48% copper. How many pounds of each alloy must he use to m
Zielflug [23.3K]

Answer:

<h2>36.14 pounds of 34% copper alloy and 9.86 pounds of 48% copper alloy</h2>

Step-by-step explanation:

        First alloy contains 34% copper and the second alloy contains 48% alloy.

We wish to make 46 pounds of a third alloy containing 37% copper.

       Let the weight of first alloy used be x in pounds and the weight of second alloy used be y in pounds.

       Total weight = 46\text{ }pounds=x+y        -(i)

      Total weight of copper = 37\%\text{ of 46 pounds = }34\%\text{ of }x\text{ pounds + }48\%\text{ of }y\text{ pounds }

       \dfrac{37\times 46}{100}=\dfrac{34x}{100}+\dfrac{48y}{100}\\\\ 34x+48y=1702        -(ii)

       Subtracting 34 times first equation from second equation,

34x+48y-34x-34y=1702-34\times46\\14y=138\\y=9.857\text{ }pounds \\x=36.143\text{ }pounds

∴ 36.14 pounds of first alloy and 9.86 pounds of second alloy were used.

5 0
3 years ago
Can someone help me with this problem please? I'll mark you as brainliest!
leonid [27]

Answer:

put a closed for on -1 and go to the left with an arrow

3 0
3 years ago
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An object that weighs 1 pound on earth weighs only 0.17 pounds on the moon. Zach's dog weighs 17 1/2 pounds on earth. How much m
PtichkaEL [24]
 its actually .16 not .17
 284.192
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