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3 years ago

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What is the pre-image of vertex A' if the rule that created the image is ry-axis(x, y) → (–x, y)? A(–4, 2) A(–2, –4) A(2, 4) A(4

, –2)

2 answers:

aev [14]3 years ago

8 0

do you have a picture

mote1985 [20]3 years ago

3 0

the answer is A on eng.

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Sliva [168]

To find A' they used the rule of multiplication, which is:

the derivative of a product of two terms is the first term times the derivative of the second term plus the second term times the derivative of the first.

To find b' they just isolated b'

6 0

3 years ago

Solving equtions in a row

yKpoI14uk [10]

1st: x = -5y - 5z - 2
2nd: x = 5y/4 - z + 19/4
3rd: x = -5y + z - 20
Not sure if this was correct, but anyways hope this helps! :)

4 0

3 years ago

I need help with B!

jolli1 [7]

Answer:

B

Step-by-step explanation:

you have to multiply f and x and then by g

4 0

3 years ago

What is 781,407 rounded to the nearest ten thousand What is 781,407 rounded to the nearest ten thousand?

faltersainse [42]

781,400 ................................

8 0

3 years ago

Read 2 more answers

For each of the following functions, (i) find the constant c so that f(x) is a pdf of a random variable X, (ii) find the cdf, F(

mel-nik [20]

Answer:

(a)

c=1/2

cdf is $F(x) = x^2$

Step-by-step explanation:

Remember that if $f$ is the pdf of a random variable X .

$\int\limits_{-\infty}^{\infty} f(x) \,dx = 1$

Then,

(a)

$\int\limits_{-\infty}^{\infty} 4xc \,dx = \int\limits_{0}^{1} 4xc \, d x = 2c = 1$

Therefore

c=1/2

and

$f(x)=2x$

then to compute the cdf, we have

$F(x) = P(X \leq x) = \int\limits_{-\infty}^{x} 2y \,dy = \int\limits_{0}^{x} 2y \, dy = x^2$

7 0

3 years ago