Question

In ΔHIJ, the measure of ∠J=90°, HI = 88 feet, and IJ = 62 feet. Find the measure of ∠I to the nearest tenth of a degree.

Answer 1

Answer:

$\huge\boxed{\sf < I = 45.2\°}$

Step-by-step explanation:

Firstly, we've to draw a triangle according to the givens. (See the attached file)

Then according to the Trigonometric Ratios:

Cos (I) = Adjacent / Hypotenuse

Cos (I) = 62 / 88

Cos (I) = 0.704

< I = Cos ⁻¹ (0.704)

< I = 45.2°

$\rule[225]{225}{2}$

Hope this helped!

~AH1807

Answer 2

Answer:

45.2

Step-by-step explanation:

hope it helps