Please help! (3 c = ? fl oz)

You have money in an account at 6% interest, compounded monthly. To the nearest year, how long

zimovet [89]

Answer:

Step-by-step explanation:

Let amount now be x , meaning principal is x

and the amount later A is 2x

A = P(1+r/n)^nt

n = 12

2x = x (1 + 0.06/12)^12t

divide through by x

2 = (1+ 0.005)^12t

2 = (1.005)^12t

Take log of both sides

log 2 = 12t log 1.005

12t = log2/log 1.005

12t = 138.975721610697

t = 138.975721610697/12

t = 11.58

t = 12 years

6 0

4 years ago

How do i check 1/3v=-5 ?

BigorU [14]

If you mean that you want to solve the equation for v, then all you need to do is to multiply both sides by 3:

$\dfrac{1}{3}v=-5 \iff 3\cdot \dfrac{1}{3}v = -5\cdot 3 \iff v=-15$

4 0

4 years ago

1/3(z+4)-6=2/3(5-z)

lara [203]

Answer:

If solving for z, z=8

5 0

3 years ago

Read 2 more answers

Before 1918, approximately 40% of the wolves in a region were male, and 60% were female. However, cattle ranchers in this area h

Goshia [24]

Answer:

P(≥ 7 males) = 0.0548

Step-by-step explanation:

This is a binomial probability distribution problem.

We are told that Before 1918;

P(male) = 40% = 0.4

P(female) = 60% = 0.6

n = 10

Thus;probability that 7 or more were male is;

P(≥ 7 males) = P(7) + P(8) + P(9) + P(10)

Now, binomial probability formula is;

P(x) = [n!/((n - x)! × x!)] × p^(x) × q^(n - x)

Now, p = 0.4 and q = 0.6.

Also, n = 10

Thus;

P(7) = [10!/((10 - 7)! × 7!)] × 0.4^(7) × 0.6^(10 - 7)

P(7) = 0.0425

P(8) = [10!/((10 - 8)! × 8!)] × 0.4^(8) × 0.6^(10 - 8)

P(8) = 0.0106

P(9) = [10!/((10 - 9)! × 9!)] × 0.4^(9) × 0.6^(10 - 9)

P(9) = 0.0016

P(10) = [10!/((10 - 10)! × 10!)] × 0.4^(10) × 0.6^(10 - 10)

P(10) = 0.0001

Thus;

P(≥ 7 males) = 0.0425 + 0.0106 + 0.0016 + 0.0001 = 0.0548

3 0

3 years ago

In a survey of 2065 adults in a certain country conducted during a period of economic uncertainty, 63 % thought that wages paid

LenKa [72]

Answer:

a) D.The interpretation is flawed. No interval has been provided about the population proportion.

b) D.The interpretation is flawed. The interpretation indicates that the level of confidence is varying.

c) A.The interpretation is reasonable.

d) C.The interpretation is flawed. The interpretation suggests that this interval sets the standard for all the other intervals, which is not true.

Step-by-step explanation:

(a) We are 95 % confident 63 % of adults in the country during the period of economic uncertainty felt wages paid to workers in industry were too low. Is the interpretation reasonable?

D.The interpretation is flawed. No interval has been provided about the population proportion.

The sample proportion alone will not give us any confidence in estimating the true proportion of adults in the country during the period of economic uncertainty felt wages paid to workers in industry were too low.

We need a 95% confidence interval to claim that the true proportion is within this interval. In this case, as the margin of error is 4%, the 95% CI is 59% and 67%.

(b) We are 91 % to 99 % confident 63 % of adults in the country during the period of economic uncertainty felt wages paid to workers in industry were too low. Is the interpretation reasonable?

D.The interpretation is flawed. The interpretation indicates that the level of confidence is varying.

The confidence is set at a fixed value and from that value the confidence interval is estimated. It still uses the sample proportion instead of the confidence interval to estimate the true proportion.

(c) We are 95 % confident the proportion of adults in the country during the period of economic uncertainty who believed wages paid to workers in industry were too low was between 0.59 and 0.67. Is the interpretation reasonable?

A.The interpretation is reasonable.

It uses the right sample data and interpret correctly the meaning of the confidence interval.

(d) In 95 % of samples of adults in the country during the period of economic uncertainty, the proportion who believed wages paid to workers in industry were too low is between 0.59 and 0.67. Is the interpretation reasonable?

C.The interpretation is flawed. The interpretation suggests that this interval sets the standard for all the other intervals, which is not true.

This confidence interval is an estimation about the parameter of the population. It doesn't give information to estimate the sampling distribution, as it only has information of one specific sample.

6 0

3 years ago