All categories

3 years ago

Hello anyone to help

Mathematics

2 answers:

Murljashka [212]3 years ago

4 0

Answer: You bought 7 books and you also bought 4 magazines

Explanation:

x = # of books purchased

y = # of magazines purchased

System of equations:

8x + 5y = 76
x + y = 11

Let’s use elimination in this case, but substitution can also work.

8x + 5y = 76
Multiply the (x + y = 11) by -8

We get:

8x + 5y = 76
-8x - 8y = -88
The xs cancel.
Add like terms.
-3y = -12
Divide by -3 on both sides
y = 4

Now plug in 4 into the (x + y = 11) equation to get x.

x + (4) = 11
Subtract 4 on both sides
x = 7

lora16 [44]3 years ago

4 0

Answer:

b+m = 11

8b + 5m = 76

b = 11-m

substitute

8(11-m)+5m = 76

88 - 8m + 5m = 76

12 = 3m

4 = m 7 = b

check

4*5 + 7*8 ?=? 76

20 + 56 = 76 the answer is correct.

Step-by-step explanation:

You might be interested in

4. -2(x+3y)= 18 Plz help me!!!

OLEGan [10]

Answer:

x+3y=-9

Step-by-step explanation:

-2(x+3y)=18

x+3y=18/-2

x+3y=-9

7 0

3 years ago

Read 2 more answers

Find out net profit after tax from the following information:

WARRIOR [948]

Answer:

Net Profit after tax Rs 15,000

Step-by-step explanation:

The computation of the net profit after tax is shown below:

Gross profit Rs. 1,25,000

Less:

Selling and distribution expenses Rs. 21,000

General and administrative expenses Rs. 75,000

Interest on loan Rs. 5,000

Gain on sale of plant Rs. 4,000

Profit before tax Rs 20,000

Less: income tax expense at 25% of Rs 20,000 Rs 5000

Net Profit after tax Rs 15,000

3 0

3 years ago

F(x)=x^2 what is g(x)

AysviL [449]

Is C g(x) = -X^2 -3

This is the answer

4 0

3 years ago

A sporting goods store sold 2.5 times as many footballs as basketballs last year. Which statement is true?

Yuri [45]

THE ANWSER IS 2 CAUSE U HAVE TO DIVIDE

3 0

3 years ago

Read 2 more answers

Sanya has a piece of land which is in the shape of a rhombus. She wants her one daughter and one son to work on the land and pro

Neporo4naja [7]

${\large{\textsf{\textbf{\underline{\underline{Given :}}}}}}$

★ Sanya has a piece of land which is in the shape of a rhombus.

★ She wants her one daughter and one son to work on the land and produce different crops, for which she divides the land in two equal parts.

★ Perimeter of land = 400 m.

★ One of the diagonal = 160 m.

${\large{\textsf{\textbf{\underline{\underline{To \: Find :}}}}}}$

★ Area each of them [son and daughter] will get.

${\large{\textsf{\textbf{\underline{\underline{Solution :}}}}}}$

Let, ABCD be the rhombus shaped field and each side of the field be $x$

[ All sides of the rhombus are equal, therefore we will let the each side of the field be $x$ ]

Now,

• Perimeter = 400m

$\longrightarrow \tt AB+BC+CD+AD=400m$

$\longrightarrow \tt x + x + x + x=400$

$\longrightarrow \tt 4x=400$

$\longrightarrow \tt \: x = \dfrac{400}{4}$

$\longrightarrow \tt x= \red{100m}$

$\therefore$ Each side of the field = 100m.

Now, we have to find the area each [son and daughter] will get.

So, For $\triangle$ ABD,

Here,

• a = 100 [AB]

• b = 100 [AD]

• c = 160 [BD]

$\therefore \tt Simi \: perimeter \: [S] = \boxed{ \sf \dfrac{a + b + c}{2} }$

$\longrightarrow \tt S = \dfrac{100 + 100 + 160}{2}$

$\longrightarrow \tt S = \cancel{ \dfrac{360}{2}}$

$\longrightarrow \tt S = 180m$

Using herons formula,

$\star \tt Area \: of \: \triangle = \boxed{\bf{{ \sqrt{s(s - a)(s - b)(s - c) } }}} \star$

where

• s is the simi perimeter = 180m

• a, b and c are sides of the triangle which are 100m, 100m and 160m respectively.

Putting the values,

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180(180 - 100)(180 - 100)(180 - 160) }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180(80)(80)(20) }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{180 \times 80 \times 80 \times 20 }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{9 \times 20 \times 20 \times 80 \times 80}$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \tt \sqrt{ {3}^{2} \times {20}^{2} \times {80}^{2} }$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = 3 \times 20 \times 80$

$\longrightarrow \tt Area_{ ( \triangle \: ABD)} = \red{ 4800 \: {m}^{2} }$

Thus, area of $\triangle$ ABD = 4800 m²

As both the triangles have same sides

So,

Area of $\triangle$ BCD = 4800 m²

Therefore, area each of them [son and daughter] will get = 4800 m²

${\large{\textsf{\textbf{\underline{\underline{Note :}}}}}}$

★ Figure in attachment.

${\underline{\rule{290pt}{2pt}}}$

7 0

2 years ago

Read 2 more answers

Hello anyone to help ​

Hello anyone to help