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sweet-ann [11.9K]
1 year ago
8

Through (-4,5) and parallel to y = -3/2x-5

Mathematics
1 answer:
Ratling [72]1 year ago
5 0

<em>**Disclaimer** Hi there! I assumed the question to be asking for a line expression. The following answer will be according to this understanding. Please let me know if I am incorrect and I will modify my answer correspondingly</em>

Answer: \Large\boxed{y-5=-\dfrac{3}{2} (x+4)}

Step-by-step explanation:

<u>Given information</u>

\text{Pass~through~point}=(x_1,~y_1)=(-4,~5)

\text{Parallel~to}:y=-\dfrac{3}{2} x-5

<u>Given equation form</u>

<em>Point-slope form is the most efficient way to write the expression</em>

\text{Point-slope form}:y-y_1=m(x-x_1)

(x_1,~y_1)=\text{A point that the line passes through}

m=\text{Slope}

<u />

<u>Determine the slope</u>

\text{Since the line is parallel to } y=-\dfrac{3}{2} x-5 \text{ , by the property of parallel}\\\text{lines, the slope of the given line is also }-\dfrac{3}{2}

\text{Therefore, m}=-\dfrac{3}{2}

<u>Substitute values into the given form</u>

y-y_1=m(x-x_1)

y-(5)=-\dfrac{3}{2} (x-(-4)

<u>Simplify the expression</u>

\Large\boxed{y-5=-\dfrac{3}{2} (x+4)}

Hope this helps!! :)

Please let me know if you have any questions

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In the diagram, AITP - ANGO. Find the values of<br> x and y.<br><br> y =<br> X=
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Answer:

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Step-by-step explanation:

Since the triangles are congruent then corresponding angles and sides are congruent, thus

∠ O = ∠ P , substitute values

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6y = 54 ( divide both sides by 6 )

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What is the answer ?
kifflom [539]
The system of inequalities is the following:

i) <span>y ≤ –0.75x
ii)</span><span>y ≤ 3x – 2

since </span>0.75= \frac{75}{100}= \frac{3}{4}, we can write the system again as 

i) y \leq - \frac{3}{4}x
ii) y  \leq 3x-2

Whenever we are asked to sketch the solution of a system of linear  inequalities, we:

1. Draw the lines
2. Color the regions of the inequalities.
3. The solution is the region colored twice.


A.

to draw the line y =- \frac{3}{4}x

consider the points: (-4, 1) and (0, 0), or any 2 other points (x,y) for which y =- \frac{3}{4}x hold.

since we have an "smaller or equal to" inequality, the line is a solid line (not dashed, or dotted).

In order to find out which region of the line to color, consider a point not on the line, for example P(1, 1), which is clearly in the upper region of the line.

For (x, y)=(1, 1) the inequality y  \leq - \frac{3}{4}x, does not hold because 

1 \leq - \frac{3}{4}*1= -\frac{3}{4} is not true,

this means that the solution is the region of the line not containing (1, 1), as shown in picture 1.


B.
similarly, to draw the solution of inequality ii) y ≤ 3x – 2, 

we first draw the line y=3x-2, using the points (0, -2) and (2, 4), or any other 2 points (x,y) for which y=3x-2 holds.

after we draw the line, we can check the point P(1, 7) which clearly is above the line y=3x-2.

for (x, y) = (1, 7), the inequality y ≤ 3x – 2 does not hold

because 7 is not ≤ 3*1-2=1, so the region we color is the one not containing P(1, 7), as shown in picture 2.


The solution of the system is the region colored with both colors, the solid lines included. Check picture 3.

the lines intersect at (0.533, -0.4) because:

–0.75x=3x-2
-0.75x-3x=-2
-3.75x=-2, that is x= -2/(-3.75)=0.533

for x=0.533, y=3x-2=3(0.533)-2=-0.4

Answer: Picture 3, the half-lines included. So the graph is in the 3rd and 4th Quadrants

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