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Mathematics

1 answer:

rjkz [21]2 years ago

4 0

Answer:

A, b, e, f

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9+3v is greater than or equal to 6

kondaur [170]

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If you take it in terms of integers,

9+3v may or may not be greater or equal to 6. It depends on the value of the variable you put in.

For eg:- if you substitute the value for v as 2 then 9+3x2=15 which is greater than 6 but if you put in -1 for v then you will get 9+3x(-1)=6

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3 years ago

PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!!

ladessa [460]

Answer:

Step-by-step explanation:

C is also possible but it is not purely random and it is not mentioned the mall is in her district.

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What is 28% of 25 in fraction form with 100 as a denominator? For example, 8/100

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8283. ye 96 when w own with uti 78252

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Prove that: (a2 - b2)3 + (b2-c2)3+ (c2-a2)3 = 3 (a+b) (b+c) (c+a) (a-b) (b-c) (c-a).

Vanyuwa [196]

$L=(a^2-b^2)^3+(b^2-c^2)^3+(c^2-a^2)^3=(*)\\\\(a^2-b^2)^3=a^6-3a^4b^2+3a^2b^4-b^6\\\\(b^2-c^2)^3=b^6-3b^4c^2+3b^3c^4-c^6\\\\(c^2-a^2)^3=c^6-3c^4a^2+3c^2a^4-a^6\\\\(*)=a^6-3a^4b^2+3a^2b^4-b^6+b^6-3b^4c^2+3b^2c^4-c^6+c^6-\dots\\\dots-3c^4a^2+3c^2a^4-a^6\\\\=-3a^4b^2+3a^2b^4-3b^4c^2+3b^2c^4-3c^4a^2+3c^2a^4\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)$

$R=3(a+b)(a-b)(b+c)(b-c)(c+a)(c-a)\\\\=3(a^2-b^2)(b^2-c^2)(c^2-a^2)\\\\=3(a^2b^2-a^2c^2-b^4+b^2c^2)(c^2-a^2)\\\\=3(a^2b^2c^2-a^4b^2-a^2c^4+a^4c^2-b^4c^2+a^2b^4+b^2c^4-a^2b^2c^2)\\\\=3(-a^4b^2+a^2b^4-b^4c^2+b^2c^4-a^2c^4+a^4c^2)\\\\L=R$

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Can someone re explain this to me

Pavlova-9 [17]

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Step-by-step explanation:

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