A square of area 121 ft² will have a side dimension of √121 ft = 11 ft. The perimeter is the length of 4 sides, so is 44 ft.
<span>DOC]<span>Venn Diagram Task – Differentiation - Summer Summit
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Answer:
DE = 13.4 cm (to 1 decimal place)
Step-by-step explanation:
Given: ABCD is a square
BC = AC = 12 cm (opposite sides of a square are congruent)
E is midpoint of BC (given)
BE = EC = 12/2 = 6 cm
CD = AB = 12 cm (opposite sides of a square are congruent)
angle ECD is a right angle (interior angles of a square are 90 deg.)
Consider right triangle ECD
DE = sqrt(EC^2+CD^2) ............. pythagorean theorem
= sqrt(6^2+12^2)
= sqrt ( 36+144 )
= sqrt (180)
= 2 sqrt(45)
= 13.416 (to three dec. places)
The remaining co-ords are (1,2) and (5,4).
Answer:
x=21/40
Step-by-step explanation:
First get common denominators
3/8 *5 to top and bottom is now 15/40
3/20 *2 to top and bottom is now 6/40
isolate the X
x-15/40=6/40
+15/40 +15/40
x=21/40
