Answer:
Jamar should hit the wall opposite to the side of the barrier(if there is a space), which will cause the ball to bounce off the wall at an angle and into Target.
A(b) = 12(b + 9) / 2
12(b + 9) = 2 A(b)
b + 9 = 2 A(b) / 12 = A(b) / 6
b = A(b)
----- - 9
6
B(a) = a
-- - 9
6
It's C
Answer:
Dh/dt = 0.082 ft/min
Step-by-step explanation:
As a perpendicular cross section of the trough is in the shape of an isosceles triangle the trough has a circular cone shape wit base of 1 feet and height h = 2 feet.
The volume of a circular cone is:
V(c) = 1/3 * π*r²*h
Then differentiating on both sides of the equation we get:
DV(c)/dt = 1/3* π*r² * Dh/dt (1)
We know that DV(c) / dt is 1 ft³ / 5 min or 1/5 ft³/min
and we are were asked how fast is the water rising when the water is 1/2 foot deep. We need to know what is the value of r at that moment
By proportion we know
r/h ( at the top of the cone 0,5/ 2) is equal to r/0.5 when water is 1/2 foot deep
Then r/h = 0,5/2 = r/0.5
r = (0,5)*( 0.5) / 2 ⇒ r = 0,125 ft
Then in equation (1) we got
(1/5) / 1/3* π*r² = Dh/dt
Dh/dt = 1/ 5*0.01635
Dh/dt = 0.082 ft/min
Answer:
Step-by-step explanation:
Since the divisor of 
is in the form of 
we use what is called Synthetic Division. Now, in this formula, −c gives the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:
4| 1 1 −17
↓ 4 20
_________
1 5 3 →
You start by placing the <em>c</em> in the top left corner, then list all the coefficients of your dividend [x² + x - 17]. You bring down the original term closest to <em>c</em> then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an x, the 5 follows right behind it, and bringing up the rear, 
giving you the quotient of 
However, in this case, since you have a remainder of 3, this gets set over the divisor.
I am joyous to assist you anytime.
