<span>Let x = the width
:
It says,"The length of a rectangle is 4 less than 3 times the width." write that as:
L = 3x - 4
:
If the perimeter is 40, find the dimensions of the rectangle.
:
We know: 2L + 2W = 40
:
Substitute (3x-4) for L and x for W
2(3x-4) + 2x = 40
:
6x - 8 + 2x = 40; Multiplied what's inside the brackets
:
6x + 2x = 40 + 8; do some basic algebra to find x; (added 8 to both sides)
:
8x = 48
:
x = 48/8
:
x = 6 which is the width
:
It said that L = 3x - 4, therefore:
L = 3(6) - 4
L = 18 - 4
L = 14; is the length
:
Check our solutions in the perimeter:
2(14) + 2(6) =
28 + 12 = 40</span>
To find the mean just add all of them then divide the result by 8. To find the median put the numbers in order. So 3, 3, 4, 4, 13, 15, 15, 16 then find the middle number, if there is not middle number (which there isn’t) add the two middle numbers (4 and 13) to get 17 then divide 17 by 2 to get 8.5 which is the median
Answer:
Socratic app
Step-by-step explanation:
it will help you
Answer:
there are two solutions:
a)
, and
b) 
Step-by-step explanation:
In the equation:
, since a perfect square with the unknown "y" is isolated on the left of the equal sign, we start by applying the square root on both sides of the equality, and then on isolating the unknown:

Therefore there are two solutions:
a)
, and
b) 
Step-by-step explanation:
y=2x−3
y=x+2
y=-3
x=3/2
for the second line
y=2
x=-2