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LuckyWell [14K]
3 years ago
13

Richard works at an ice cream shop. Regular comes get 2 scoops of ice cream, large cones get 3 scoops. One hotnsaturday Richard

scooped 234 regular cones and 156 large cones. One scoop of ice cream is 3 ounces. A tub of ice cream weighs 10 pounds. How many tubs of ice cream did Richard use to make the cones
Mathematics
1 answer:
kolbaska11 [484]3 years ago
7 0

Given that one regular cone uses 2 scoops of icecream

Richard scooped 234 regular cones

so amount of scoope in regular cones = 2*234 scoops.

Given that one large cone uses 3 scoops of icecream

Richard scooped 156 large cones.

so amount of scoope in large cones = 3*156 scoops.

Total scoops used = 2*234+3*156= 468+468= 936 scoops

Given that one scoop of ice cream = 3 ounce

then 936 scoops = 936*3 ounce = 2808 ounce

Given that 1 tube contains 10 pounds.

There are 16 ounces into 1 pound

so that means 1 tube contains 10*16= 160 ounce.

Now we want to calculate numbe of tubes used

so we will divide weight of total used scoops by weight of 1 tube

which is 2808/160 =17.55

Hence answer is approx 18 tubes.

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To gain a pass a student needs to achieve a mean of at least 60% in eight tests. In the first seven
Tanzania [10]

Step-by-step explanation:

the mean value is the sum of all data points divided by the number of data points.

first we have 7 tests and their mean value :

(t1 + t2 + t3 + t4 + t5 + t6 + t7) / 7 = 54

that means

(t1 + t2 + t3 + t4 + t5 + t6 + t7) = 54 × 7 = 378

in order for the mean value to be at least 60% after 8 tests, we need to add a t8, so that

(t1 + t2 + t3 + t4 + t5 + t6 + t7 + t8) = 60 × 8 = 480

because only then we have

(t1 + t2 + t3 + t4 + t5 + t6 + t7 + t8) / 8 = 60

and the student passes.

so,

(t1 + t2 + t3 + t4 + t5 + t6 + t7) + t8 = 480

378 + t8 = 480

t8 = 480 - 378 = 102%

the student would have to achieve 102% on the 8th test.

which would be normally impossible, but maybe the tests involve some bonus points.

6 0
1 year ago
Plz help me with this
saul85 [17]

Your answer would be the second option, (-4,5).

We can find this by substituting in each point into the equation y < |x - 3| and seeing if it is true.

For the first one you get 1 < |2 - 1|. |2 - 1| = |-1| = 1, and 1 cannot be less than itself, so this is false.

For the second one you get 5 < |-4 - 3|. |-4 - 3| = |-7| = 7, and 5 is indeed less than 7, so this is correct.

I hope this helps!

7 0
2 years ago
Read 2 more answers
Find the domain of the following relation. <br> R={(19,96),(20,101),(21,106),(22,111)}
mafiozo [28]
(x, y)

The domain are all the x-values, the range are all the y-values.

R={(19,96),(20,101),(21,106),(22,111)}

The domain is: 19, 20, 21, and 22
The range is: 96, 101, 106, and 111
7 0
2 years ago
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What is the rule for the reflection?<br> Pls help me
Luda [366]
I want to say B
This is filler to answer
6 0
2 years ago
Which answer is correct? It wouldn’t let me click mathematics btw
Bad White [126]
6)
KM bisects on <NKL so m<MKN = m<MKL = 3x + 5

2(m<MKL) + m<JKN = 180
2(3x+5) + 8x + 2 = 180
6x + 10 + 8x + 2 = 180
14x + 12 = 180
14x = 168
    x = 12

so 
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answer
b. 41

7)

2 supplementary has sum = 180
x + x + 14 = 180
2x + 14 = 180
2x = 166
  x = 83
  x + 14 = 83 + 14 = 97

2 angles are 83 and 97

answer
b. 83, 97
7 0
3 years ago
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