It's a quadratic with a positive x² coefficient, so a CUP, with a minimum
f(x) = 2x² -12 x + 13
= 2(x² - 6x) + 13
= 2(x - 3)² - 2(9) + 13
f(x) = 2(x - 3)² - 5
Since x-3 is always zero or positive the least value is
f(3) = -5
Answer: -5
Answer:
x=3.5
Step-by-step explanation:
1. Multiply
18x-12=5x+30
2. Move the x's to one side
12x= 42
3. Isolate the variable by dividing
(-4,0) ; (-7, -14)
