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Naddika [18.5K]

3 years ago

10

URGENT CASE, need help please, Trigonometric Functions

1 answer:

frez [133]3 years ago

5 0

Dude use the formula of height and distance to find the height of the trangle and then you can find the other side length using Pythagorus theorem

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An explosion causes debris to rise vertically with an initial speed of 120 feet per second. The formula h equals negative 16 t s

Novay_Z [31]

Answer:

The debris will be at a height of 56 ft when time is <u>0.5 s and 7 s.</u>

Step-by-step explanation:

Given:

Initial speed of debris is, $s=120\ ft/s$

The height 'h' of the debris above the ground is given as:

$h(t)=-16t^2+120t$

As per question, $h(t)=56\ ft$ . Therefore,

$56=-16t^2+120t$

Rewriting the above equation into a standard quadratic equation and solving for 't', we get:

$-16t^2+120t-56=0\\\textrm{Dividing by -8 throughout, we get}\\\frac{-16}{-8}t^2+\frac{120}{-8}t-\frac{56}{-8}=0\\2t^2-15t+7=0$

Using quadratic formula to solve for 't', we get:

$t=\frac{-b\pm \sqrt{b^2-4ac}}{2a}\\\\t=\frac{-(-15)\pm \sqrt{(-15)^2-4(2)(7)}}{2(2)}\\\\t=\frac{15\pm \sqrt{225-56}}{4}\\\\t=\frac{15\pm\sqrt{169}}{4}\\\\t=\frac{15\pm 13}{4}\\\\t=\frac{15-13}{4}\ or\ t=\frac{15+13}{4}\\\\t=\frac{2}{4}\ or\ t=\frac{28}{4}\\\\t=0.5\ s\ or\ t=7\ s$

Therefore, the debris will reach a height of 56 ft twice.

When time $t=0.5\ s$ during the upward journey, the debris is at height of 56 ft.

Again after reaching maximum height, the debris falls back and at $t=7\ s$ , the height is 56 ft.

5 0

3 years ago

Equivalent expression to 3(4m-2)-2(m+5

wolverine [178]

Answer:

10m - 16

Step-by-step explanation:

1. Perform the indicated multiplication. We get 12m - 6 - 2m - 10.

2. Combine like terms: We get 10m - 16

4 0

3 years ago

Expand each expression

matrenka [14]

Answer:

Option B - $\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x$

Step-by-step explanation:

Given : Expression $\ln(\frac{4y^5}{x^2})$

To find : Expand each expression ?

Solution :

Using logarithmic properties,

$\ln (\frac{A}{B})=\frac{\ln A}{\ln B}=\ln A-\ln B$

and $\ln (AB)=\ln A+\ln B$

Here, A=4y^5 and B=x^2

$\ln(\frac{4y^5}{x^2})=\frac{\ln 4y^5}{\ln x^2}$

$\ln(\frac{4y^5}{x^2})=\ln 4y^5-\ln x^2$

$\ln(\frac{4y^5}{x^2})=\ln 4+\ln y^5-\ln x^2$

Using logarithmic property, $\logx^a=a\log x$

$\ln(\frac{4y^5}{x^2})=\ln 4+5\ln y-2\ln x$

Therefore, option B is correct.

3 0

3 years ago

Read 2 more answers

Which statement is about determining 1/10 divided 5 is true?

Viktor [21]

Answer: 1/50 or C

Step-by-step explanation:

I did the test :D

8 0

3 years ago

Read 2 more answers

Answer Question Pls? I need Help!!

QveST [7]

Answer:

option D

Step-by-step explanation:

Take the two through which the lines passes.

Let it be ( -5 , 0) and ( 0 , -3)

Step 1 : Find slope, m

$Slope,m = \frac{y_2 -y_1}{x_2 - x_1}$

$= \frac{-3-0}{0--5} = \frac{-3}{5}$

Step 2 : Find the equation

$(y - y_ 1) = m( x - x_1)\\\\( y - 0) = \frac{-3}{5} (x --5) \\\\y = -\frac{3}{5}( x + 5 ) \\\\y = -\frac{3}{5}x - 3$

8 0

3 years ago