I believe that its easier to understand the multiplication of a radical than that of a polynomial.
<h3>How to illustrate the information?</h3>
In mathematics, a radical is the opposite of an exponent that is represented with a symbol '√' also known as root.
A polynomial is an expression which is composed of variables, constants and exponents, that are combined using the mathematical operations such as addition, subtraction, multiplication and division.
When multiplying radicals with the same index, multiply under the radical, and then multiply in front of the radical. An example is:
= 3✓2 × 4✓2
= 12✓4
= 12 × 2
= 24
The multiplication of a radical is easier.
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Answer:
y=-5/2+x
Step-by-step explanation:
Answer:
<em>25 mg. is lighter than 25 cg.</em>
<em />
Step-by-step explanation:
<em>Well,</em>
<em />
<em>The prefix "milli" means thousandth and the prefix "centi" means hundredth. So a milligram will be one-tenth of a centigram.</em>
<em />
<em>10 mg. = 1 cg.</em>
<em>25 mg. = 2.5 cg.</em>
<em />
<em>2.5 cg. < 25 cg.</em>
<em />
<em>25 mg. is lighter than 25 cg.</em>
Answer:
F(x) and g(x) are not inverse functions.
Step-by-step explanation:
In order to calculate the inverse function of a function, we have to isolate X and after that, we change the variables.
As our function f(x) is a exponentian function, we can apply logarithm with base 10 (log) in both sides in order to isolate X. Remember that log10=1.
![[tex]y=10^{(x+\frac{2}{3}) }\\\\log y=log 10^{(x+\frac{2}{3}) }\\log y = (x+\frac{2}{3}) . log10\\\frac{log Y}{log10} = (x+\frac{2}{3})\\\frac{log Y}{1} = (x+\frac{2}{3})\\log Y-\frac{2}{3}=x](https://tex.z-dn.net/?f=%5Btex%5Dy%3D10%5E%7B%28x%2B%5Cfrac%7B2%7D%7B3%7D%29%20%7D%5C%5C%5C%5Clog%20y%3Dlog%2010%5E%7B%28x%2B%5Cfrac%7B2%7D%7B3%7D%29%20%7D%5C%5Clog%20y%20%3D%20%28x%2B%5Cfrac%7B2%7D%7B3%7D%29%20.%20log10%5C%5C%5Cfrac%7Blog%20Y%7D%7Blog10%7D%20%3D%20%28x%2B%5Cfrac%7B2%7D%7B3%7D%29%5C%5C%5Cfrac%7Blog%20Y%7D%7B1%7D%20%3D%20%28x%2B%5Cfrac%7B2%7D%7B3%7D%29%5C%5Clog%20Y-%5Cfrac%7B2%7D%7B3%7D%3Dx)
[/tex]
Now we change the variables.
F(x) and g(x) are not inverse functions.
<span>The answer should be this ∠ACB ≅ ∠DCB. I hope this helps</span>
