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Answer:
4) 6x
5) 2x +3
Step-by-step explanation:
We can work both these problems at once by finding an applicable rule.
![\text{For $f(x)=ax^n$}\\\\\lim\limits_{h\to 0}\dfrac{f(x+h)-f(x)}{h}=\lim\limits_{h\to 0}\dfrac{a(x+h)^n-ax^n}{h}\\\\=\lim\limits_{h\to 0}\dfrac{ax^n+anx^{n-1}h+O(h^2)-ax^n}{h}=\boxed{anx^{n-1}}](https://tex.z-dn.net/?f=%5Ctext%7BFor%20%24f%28x%29%3Dax%5En%24%7D%5C%5C%5C%5C%5Clim%5Climits_%7Bh%5Cto%200%7D%5Cdfrac%7Bf%28x%2Bh%29-f%28x%29%7D%7Bh%7D%3D%5Clim%5Climits_%7Bh%5Cto%200%7D%5Cdfrac%7Ba%28x%2Bh%29%5En-ax%5En%7D%7Bh%7D%5C%5C%5C%5C%3D%5Clim%5Climits_%7Bh%5Cto%200%7D%5Cdfrac%7Bax%5En%2Banx%5E%7Bn-1%7Dh%2BO%28h%5E2%29-ax%5En%7D%7Bh%7D%3D%5Cboxed%7Banx%5E%7Bn-1%7D%7D)
where O(h²) is the series of terms involving h² and higher powers. When divided by h, each term has h as a multiplier, so the series sums to zero when h approaches zero. Of course, if n < 2, there are no O(h²) terms in the expansion, so that can be ignored.
This can be referred to as the <em>power rule</em>.
Note that for the quadratic f(x) = ax^2 +bx +c, the limit of the sum is the sum of the limits, so this applies to the terms individually:
lim[h→0](f(x+h)-f(x))/h = 2ax +b
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4. The gradient of 3x^2 is 3(2)x^(2-1) = 6x.
5. The gradient of x^2 +3x +1 is 2x +3.
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If you need to "show work" for these problems individually, use the appropriate values for 'a' and 'n' in the above derivation of the power rule.
In this question, the volume of the cone is needed. The equation used to determine the volume of the cone is (1/3)π(r²)h
To solve for the volume,
V = (1/3)π(3²)(10)
= (1/3)(9)(10)π
= (3)(10)π
= 30π cm³
The correct answer is the first option which is 30π cm³.
Answer:
The 1st and 2nd graph are functions while the 3rd and 4th aren't.
Step-by-step explanation:
The first and second graph doesn't have more than one output for each input. The third and fourth graph isn't a function since there's more than one output for the same input given. If you do the vertical line test, then you'll know which one is a function and which one is not a function. Hope this helps :)
Answer:
7/10
Step-by-step explanation:
♥Yes.
♥When you divide the numerator by the denominator you get <span>0.66666666666
and that is greater then 1/5 divided, </span><span>0.2.
<span><span><span><span><span>♥Therefore yes.</span></span></span></span></span></span>