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Schach [20]
3 years ago
6

Pls help meeeeeeeeeee

Mathematics
1 answer:
Vera_Pavlovna [14]3 years ago
7 0

Answer:

A. t = -2h + 32

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Jenny used 15 centimeters of tape to wrap 5 presents. How much tape will Jenny need in all if she has to wrap 10 presents? Assum
Scorpion4ik [409]

Answer:

30

Step-by-step explanation:

15cm for 5

5 x 2=10

15 x 2 = 30

7 0
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Bobby and Petra are running a lemonade stand and they charge 45 cents for each glass of lemonade. To break even they must make $
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Step-by-step explanation:

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3 years ago
The attention span of children (ages 3 to 5) is claimed to be Normally distributed with a mean of 15 minutes and a standard devi
Agata [3.3K]

Answer:

If the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

Step-by-step explanation:

We are given the following in the question:

Population mean, μ = 15 minutes

Sample size, n = 10

Alpha, α = 0.05

Population standard deviation, σ = 4 minutes

First, we design the null and the alternate hypothesis

H_{0}: \mu = 15\text{ minutes}\\H_A: \mu > 15\text{ minutes}

Since the population standard deviation is given, we use one-tailed z test to perform this hypothesis.

Formula:

z_{stat} = \displaystyle\frac{\bar{x} - \mu}{\frac{\sigma}{\sqrt{n}} }

Now, z_{critical} \text{ at 0.05 level of significance for one tail} = 1.64

Thus, we would reject the null hypothesis if the z-statistic is greater than this critical value.

Thus, we can write:

z_{stat} = \displaystyle\frac{\bar{x} - 15}{\frac{4}{\sqrt{10}} } > 1.64\\\\\bar{x} - 15>1.64\times \frac{4}{\sqrt{10}}\\\bar{x} - 15>2.07\\\bar{x} > 15+2.07\\\bar{x} > 17.07

Thus, the decision rule would be if the observed sample mean is greater than 17.07 minutes, then we would reject the null hypothesis.

6 0
4 years ago
What was their velocity
shutvik [7]

Answer:

Step-by-step explanation:

Wat is the question lol

5 0
3 years ago
Which three comparisons are true?
Leya [2.2K]

Answer:

The answer is 4/8=2/4 because 4/8 simplifying is 2/4 or 1/2

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