Answer:
294.14cm^2
Explanation:
First find the area of the whole piece of paper:
32*14=448
Then find the area of the two semicircles, semicircle + semicircle = 1 circle:
Area of a circle= (radius squared)(pi):
(7^2)(3.14) = 153.86
Subtract the area of the two semicircles from the whole paper area:
448-153.86 = 294.14
I hope this isn’t too confusing :)
Answer:
64 degrees
It says I have to have over twenty characters. this sentence does not have to be read
First term ,a=4 , common difference =4-7=-3, n =50
sum of first 50terms= (50/2)[2×4+(50-1)(-3)]
=25×[8+49]×-3
=25×57×-3
=25× -171
= -42925
derivation of the formula for the sum of n terms
Progression, S
S=a1+a2+a3+a4+...+an
S=a1+(a1+d)+(a1+2d)+(a1+3d)+...+[a1+(n−1)d] → Equation (1)
S=an+an−1+an−2+an−3+...+a1
S=an+(an−d)+(an−2d)+(an−3d)+...+[an−(n−1)d] → Equation (2)
Add Equations (1) and (2)
2S=(a1+an)+(a1+an)+(a1+an)+(a1+an)+...+(a1+an)
2S=n(a1+an)
S=n/2(a1+an)
Substitute an = a1 + (n - 1)d to the above equation, we have
S=n/2{a1+[a1+(n−1)d]}
S=n/2[2a1+(n−1)d]
Answer:
(-2, 5)
Step-by-step explanation:
we subtract 6x+3y=3 by 2x+3y=11 to get 4x=-8.
we divide both sides by 4 to get x. x=-2
We subsitute -2 for the second equation to get:
2(-2)+3y=11
=-4+3y=11
=3y=15
y=5
