T = 5 a
i = 4% aa
j = 1200
c = ...
j = cit/100
c = 100j / it
c = 100*1200 / 4*5
c = 120000 / 20
c = 12000/2
c = 6000
montante
M = c+j
M = 6000+1200
M = 7200
Answer:
896
Step-by-step explanation:
Let's talk first about how many 3 digit numbers there are. The first 3 digit number is 100 and the last is 999. So there are 999-100+1 numbers that are 3 digits long. That simplifies to 900.
Now let's find how many of those have a sum for the digits being 1, then 2 ? Then take that sum away from the 900 to see how many 3 digit numbers have the sum of their digits being more than 2.
3 digit numbers with sum of 1:
The first and only number is 100 since 1+0+0=1.
We can't include 010 or 001 because these aren't really three digits long.
3 digit numbers with sum of 2:
The first number is 101 since 1+0+1=2.
The second number is 110 since 1+1+0=2.
The third number is 200 since 2+0+0=2.
That's the last of those. We could only use 0,1, and 2 here.... Anything with a 3 in it would give us something larger than or equal to 3.
So there are 900-1-3 numbers who are 3 digits long and whose sum of digits is greater than 2.
This answer simplifies to 896.
Answer:
20/81
Step-by-step explanation:
Without parentheses, it is hard to tell what you are dividing. We assume you want ...
(4/9)/(9/5)
Then ...
_____
As written (without parentheses), your expression is evaluated left to right, so evaluates to ...
4/(9·9·5) = 4/405
Answer: Options 'C' and 'E' are correct.
Step-by-step explanation:
Since we have given that
Quantity of snowfall in February at Delphine's house be f centimeters
Quantity of snowfall in March at Delphine's house be 40% more than in February.
According to question,
So, Options 'C' and 'E' are correct.
i.e. C) 1.4f
E) 
