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3 years ago

Somebody please help it would be much appreciated.

Mathematics

2 answers:

Sav [38]3 years ago

7 0

Answer:

Step-by-step explanation:

as you can see test a is further away from the ruler you have to put it at 0 so that you can get your answer I am not sure if it's correct or not

Likurg_2 [28]3 years ago

6 0

Answer:

Step-by-step explanation:

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Step-by-step explanation:

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3 years ago

Given the linear equation 2x + y = 6, perform the necessary operations to put the equation into the proper general form. Explain

likoan [24]

Step-by-step explanation:

The general equation is y = mx + c...

The given equation is 2x + y = 6

Firstly, move everything on the left except the y to the right.i.e.

y = 6 - 2x

Secondly, rearrange the values on the right to look just like the general equation.

y = -2x + 6

The equation is now in proper general form because it matches the format laid down.

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4 years ago

The hypotenuese of an isosceles right triangle is 13 inches. The midpoints of its sides are connected to form an inscribed trian

Georgia [21]

Answer:

The Sum of the areas of theses triangles is 169/3.

Step-by-step explanation:

Consider the provided information.

The hypotenuse of an isosceles right triangle is 13 inches.

Therefore,

$x^2+x^2=169\\2x^2=169\\x=\frac{13}{\sqrt{2} }$

Then the area of isosceles right triangle will be: $A=\frac{1}{2} x^2$

Therefore the area is: $A=\frac{169}{4}$

It is given that sum of the area of these triangles if this process is continued infinitely.

We can find the sum of the area using infinite geometric series formula.

$S=\frac{a}{1-r}$

Substitute $a=\frac{169}{4} \ and\ r=\frac{1}{4}$ in above formula.

$S=\frac{\frac{169}{4}}{1-\frac{1}{4}}$

$S=\frac{\frac{169}{4}}{\frac{3}{4}}$

$S=\frac{169}{3}$

Hence, the Sum of the areas of theses triangles is 169/3.

7 0

3 years ago