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2 years ago

15

While taking inventory if his pastry shop Noah realize that he had 4 7/8 boxes of baking powder yesterday but the supply is now

down to the 1/2 of a box how much more baking powder did Noah have yesterday?

1 answer:

Nuetrik [128]2 years ago

8 0

Answer:

4 3/8

Step-by-step explanation:

4 and 7/8 - 1/2 = 4 and 7/8 - 4/8 = 4 and 3/8 of a box more

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PLEASE HELP!!! TRIG, Theres a picture!!

BartSMP [9]

Answer:

<h2>The answer is option C</h2>

Step-by-step explanation:

$3( { \tan }^{2} \theta - { \sec }^{2} \theta)$

Using trigonometric identities

That's

$1 + { \tan }^{2} \theta = { \sec }^{2} \theta$

Rewrite the expression

That's

$3({ \tan }^{2} \theta - (1 + { \tan }^{2} \theta)) \\$

Simplify

We have

$3({ \tan }^{2} \theta - 1 - { \tan }^{2} \theta) \\ 3({ \tan }^{2} \theta - { \tan }^{2} \theta - 1)$

So we have

3( - 1)

We have the final answer as

<h2>- 3</h2>

Hope this helps you

3 0

2 years ago

Carli and Angela share a cell phone plan and split the bill each month. Last month, their total bill was $109. Carli went over h

Lubov Fominskaja [6]

Answer:

B

Step-by-step explanation:

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2 years ago

What is the solution of /x2+49 = x+5?

ICE Princess25 [194]

Answer: x= 12/5 or 2 2/5

Step-by-step explanation:

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2 years ago

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Will someone help me

faust18 [17]

Answer:

1.one solution

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Step-by-step explanation:

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If we wanted to create a new 90% confidence interval from a different sample for the proportion of those with a two on one date

slava [35]

Answer: 271

Step-by-step explanation:

The formula we use to find the sample size is given by :-

$n=p(1-p)(\dfrac{z_{\alpha/2}}{E})^2$

, where $z_{\alpha/2}$ is the two-tailed z-value for significance level of $(\alpha)$

p = prior estimation of the proportion

E = Margin of error.

If prior estimation of the proportion is unknown, then we take p= 0.5 , the formula becomes

$n=0.5(1-0.5)(\dfrac{z_{\alpha/2}}{E})^2$

$n=0.25(\dfrac{z_{\alpha/2}}{E})^2$

Given : Margin of error : E= 0.05

Confidence level = 90%

Significance level $\alpha=1-0.90=0.10$

Using z-value table , Two-tailed z-value for significance level of $0.10$

$z_{\alpha/2}=1.645$

Then, the required sample size would be :

$n=0.25(\dfrac{1.645}{0.05})^2$

Simplify,

$n=270.6025\approx271$

Hence, the required minimum sample size =271

3 0

3 years ago