2 and 5/8: You would go from the number the fraction is closest to, and then add the fraction itself.
The speed of the plane after it encounters the wind is C.285mph
<h3>How to calculate the speed of the plane when it encounters the wind?</h3>
Since the plane takes off from an airport on a bearing of 270° and travels at a speed of 320 mph it's velocity is v = (320cos270°)i + (320sin270°)j
= (320 × 0)i + (320 × -1)j
= 0i - 320j
= - 320j mph
Also, the plane encounters a 35 mph wind blowing directly north. The velocity of the wind is v' = 35j mph
So, the velocity of the plane after it encounters the wind is the resultant velocity, V = v + v'
= -320j mph + 35j mph
= -285j mph
So, the speed of the plane after it encounters the wind is the magnitude of V = |-285j| mph
= 285 mph
So, the speed of the plane after it encounters the wind is C.285mph
Learn more about speed of plane here:
brainly.com/question/3387746
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Answer:
True
Step-by-step explanation:
the graph makes a loop and both ends go in the same direction
A circle equation is (x – h)^2<span> + (y – k)^</span>2<span> = r^</span><span>2 where (h,k) is the center and r is the radius. Now all we have to do is plug in the variables.
Since (h,k)=(5,4) and r= 6
The answer would be C.
Your welcome ;)
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