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Ostrovityanka [42]
3 years ago
12

Pentagon ABCDE is graphed with the following vertices A(4,6), B(9,6), C(7,1), D(4,0), and E(1,3). What would point C' be after a

reflection over the y=axis?
IF YOU ANSWER THIS CORRECTLY I WILL GIVE 50 MORE POINTS!!!!!
Mathematics
1 answer:
Artist 52 [7]3 years ago
7 0

Answer:

(-7,1)

Step-by-step explanation:

over the y axis means the opposite way to the right or the left . the 7 will become -7 because on the other side the x-axis is made of negative numbers.

remember this to graph a number , it is like going in an elevator you have yo get in then go up or down.

You might be interested in
E
AlexFokin [52]

For this case we have that by definition, the point-slope equation of a line is given by:

y-y_ {0} = m (x-x_ {0})

Where:

m: It's the slope

(x_ {0}, y_ {0}): It is a point through which the line passes

According to the statement data we have:

m = 5\\(x_ {0}, y_ {0}): (- 8,1)

Substituting we have:

y-1 = 5 (x - (- 8))

By law of signs of multiplication we have to:

- * - = +\\y-1 = 5 (x + 8)

Answer:

The requested equation is: y-1 = 5 (x + 8)

5 0
3 years ago
This is the term in a polynomial without a variable
alexandr1967 [171]
It is a constant. hope this helps

4 0
3 years ago
Find the MIDPOINT between (-12, – 7)<br> and (-8,-4).
DanielleElmas [232]

so you take the average of the x coordinates and the average of the y coordinates to get the midpoint like this

7 0
3 years ago
find an equation for the nth term of the sequence. -3, -12, -48, -192, ... select one: a. an = 4 • -3n 1 b. an = -3 • 4n - 1 c.
Andrews [41]
-3;-12;-48;-192;...\\\\It's\ the\ geometric\ sequence:a_n=a_1r^{n-1}\\\\a_1=-3;\ a_2=-12\\\\r=a_2:a_1\to r=-12:(-3)=4\\\\\boxed{a_n=-3\cdot4^{n-1}}\to\fbox{b.}
3 0
3 years ago
Read 2 more answers
Find the slope of the line.
Lera25 [3.4K]

Answer:

  = -3

Step-by-step explanation:

Find 2 points

(-2, 4) and (1,-5)

We can use the slope formula

m = (y2-y1)/(x2-x1)

    = (-5-4)/(1 - -2)

    = -9/(1+2)

    = -9/3

  = -3

4 0
3 years ago
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