Answer:
x=2
Step-by-step explanation:
use distributive property: x^2+2x-1=4
remove the -1 by adding 1 on both sides: x^2+2x=5
use the guadratic fromula: ax²+bx+c=0
plug in the equation x^2+2x-5=0
a,b and c are the coefficients to plug into the formula
a=1, b=2, c=-1
Finally, you will find that x=2
Yes I love this problem so good
Just do the whole process backwards
700*0.01=7
7-2.84=4.16
4.16/0.8=5.2
5.2+1.05=6.25
An exponential model can be described by the function
![f(x) = a(b)^x](https://tex.z-dn.net/?f=f%28x%29%20%3D%20a%28b%29%5Ex)
where: a is the initial population or the starting number, b is the base and x is the number of periods elapsed.
When the base of an exponential model is greater than 1 it is called a growth factor, but when it is less than 1 it is called a decay factor.
Given the exponential model
![n=20.5(0.6394)^t](https://tex.z-dn.net/?f=n%3D20.5%280.6394%29%5Et)
n is the final output of the exponential model, 20.5 is the starting number, 0.6394 is the base and t is the number of periods/time elapsed.
Here, the base is 0.6394 which is less than 1, hence a decay factor.
Therefore, <span>the
base, b, of the exponential model is 0.6394; It is a
decay factor.</span>