Answer:
2 real solutions
Step-by-step explanation:
We can use the determinant, which says that for a quadratic of the form ax² + bx + c, we can determine what kind of solutions it has by looking at the determinant of the form:
b² - 4ac
If b² - 4ac > 0, then there are 2 real solutions. If b² - 4ac = 0, then there is 1 real solution. If b² - 4ac < 0, then there are 2 imaginary solutions.
Here, a = 6, b = -20, and c = 1. So, plug these into the determinant formula:
b² - 4ac
(-20)² - 4 * 6 * 1 = 400 - 24 = 376
Since 376 is clearly greater than 0, we know this quadratic has 2 real solutions.
<em>~ an aesthetics lover</em>
Answer:
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Answer: m = 10
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Answer:
3^(k+2) = 9m/ 26
Step-by-step explanation:
Let 3^k = y :
y×3^3-y = m
26y = m
26×3^k = m
3^(k+2) = m/26×3^2
Therefore 3^(k+2) = 9m/26
10 ^-4
Use the negative exponent rule to get:
1/10^4 = 1/10,000 (fraction answer) or 0.0001 (decimal answer)
