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Vadim26 [7]
3 years ago
7

The domain of u(x) is the set of all real values except 0 and the domain of v(x) is the set of all real values except 2. What ar

e the restrictions on the domain of (u circle v) (x)?
Mathematics
1 answer:
beks73 [17]3 years ago
5 0

Answer:

A≈1075.21

d Diameter

37

d

r

r

r

d

d

C

A

Using the formulas

A=

π

r

2

d=

2

r

Solving forA

A=

1

4

π

d

2

=

h1

4

π

37

2

≈

1075.21009

Step-by-step explanation:

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A student earned a grade of 80% on a math test that had20 problems. How many problems on this test did the student answer correc
Georgia [21]

Answer:

Only 16 problems correct

Step-by-step explanation:

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2 years ago
Find the 8th term of the sequence with formula tn= 7+2 (n-1)
stellarik [79]

Answer:

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Step-by-step explanation:

7+2(n-1)

we have our n as 8

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3 0
1 year ago
Please help me explain as well. I will give brainliest.
garik1379 [7]

Answer:

Step-by-step explanation:

6 0
3 years ago
This is due today I don’t get it.
erik [133]

Answer:

1. A, C, and D are on the line.

1st graph:

1. The slope is 2/3.

2. The y-intercept is (0, -1)

3. The equation is y = 2/3x - 1

2nd graph:

1. The slope is 4.

2. The y-intercept is (0, -3)

3. The equation is y = 4x - 3

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
I need help please it’s due tomorrow.......
Sholpan [36]
Let
x-------> the width of the rectangular area
y------> the length of the rectangular area

we know that
y=x+15------> equation 1
perimeter of a rectangle=2*[x+y]
2x+2y <= 150-------> equation 2

substitute 1 in 2
2x+2*[x+15] <=150--------> 2x+2x+30 <=150----> 4x <=150-30
4x <= 120---------> x <= 30
the width of the rectangular area is at most 30 ft
y=x+15
for x=30
y=30+15------> y=45
 the length of the rectangular area is at most 45 ft

see the attached figure
the solution is<span> the shaded area</span>

4 0
3 years ago
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