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3 years ago

Does anyone know how to do this?? I don’t understand. I need help please ASAP! Tysm

Mathematics

1 answer:

bixtya [17]3 years ago

3 0

17. 30

19. 58

21. 55

23. 23

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A student selecting 3 classes for Winter quarter there are 4 drawing and design courses 3 general education courses and 3 other

pychu [463]

Answer:

36 possible class schedules

Step-by-step explanation:

1st - 4 ways

2nd - 3 ways

3rd - 3 ways

4 x 3 x 3 = 36 possible class schedules

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2 years ago

Can someone please help? its urgent!!!<br><br><br> y=2x+1 for x = -2 , -1 , 0 , 1 , and 2

leonid [27]

Answer:

hello :

y = –2x – 1....(1)

y = 3x–1.....(2)

by (1) and (2) : 3x-1 = -2x-1

5x =0

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Step-by-step explanation:

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3 years ago

21. What must be added to -9 to have a sum of 20?

Inga [223]

Answer:

21C

22D

23B

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Step-by-step explanation:

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2 years ago

Read 2 more answers

Which of the following theorems verifies that triangle STU is congruent to triangle XYZ

Leni [432]

Answer:

B. HL

Step-by-step explanation:

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2 years ago

2(a³+b²+11)+1(3+a³+b+11)

Ann [662]

Answer:

$2(a^3+b^2+11)+1(3+a^3+b+11)=3a^3+2b^2+b+36$

Step-by-step explanation:

I assume that you need simplification of the given expression.

The given expression is:

$2(a^3+b^2+11)+1(3+a^3+b+11)$

Using distributive property and multiplying 2 inside the parenthesis and 1 inside the other parenthesis. This gives,

$2(a^3+b^2+11)=2\times a^3+2\times b^2+2\times 11\\2(a^3+b^2+11)=2a^3+2b^2+22\\\\1(3+a^3+b+11)=1\times 3+1\times a^3+1\times b+1\times 11\\1(3+a^3+b+11)=3+a^3+b+11=a^3+b+14$

Therefore, $2(a^3+b^2+11)+1(3+a^3+b+11)$ is equal to:

$2a^3+2b^2+22+a^3+b+14$

Now, combining like terms using the commutative property of addition, we get:

$=(2a^3+a^3)+2b^2+b+(22+14)\\=3a^3+2b^2+b+36$

Therefore, the simplified form is $3a^3+2b^2+b+36$

8 0

3 years ago