Question

Which is the equation of the given line? (-10,-7) (3,-7)

Answer 1

Answer:  $y=-7$

Step-by-step explanation:

The equation of the line in Slope-intercept form is:

$y=mx+b$

Where "m" is the slope of the line and "b" is the y-intercept.

Find the slope with this formula:

$m=\frac{y_2-y_1}{x_2-x_1}$

Given the points (-10,-7) (3,-7), substitute values into the formula. Then:

$m=\frac{-7-(-7)}{-10-3}\\\\m=\frac{0}{-13}\\\\m=0$

Substitute the slope and any point into  $y=mx+b$ and solve for "b":

$-7=0x+b\\b=-7$

Then, substituting "m" and "b" into the equation  $y=mx+b$, you get that the equation of this line is:

 $y=0x-7$

 $y=-7$