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Dominik [7]
3 years ago
5

2x + 3y + x +7 Like terms

Mathematics
2 answers:
Serjik [45]3 years ago
4 0

Answer:

3x+3y+7

Step-by-step explanation:

2x+x+3y+7

3x+3y+7

igor_vitrenko [27]3 years ago
3 0

Answer:

3x+3y+7

Step-by-step explanation:

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Which of the following is a solution of y |x|-6. (-5,1) (-1,-5) (5,-1)
Artemon [7]
Assuming you forgot the equal sign

y=|x|-6

test each
(x,y)
(-5,1)
1=|-5|-6
1=5-6
1=-1
fasle

(-1,-5)
-5=|-1|-6
-5=1-6
-5=-5
true

(5,-1)
-1=|5|-6
-1=5-6
-1=-1

the answer is
(-1,-5) and (5,-1)
7 0
4 years ago
Read 2 more answers
Evaluate the function.<br> f(x) = –22 – 9x + 20<br> Find f(9)
Alenkasestr [34]

Answer:

f(9)=-22-9(9)+20=-83

Step-by-step explanation:

f(9) means x = 9, Just substitute 9 into the function.

-9(9) = -81

-22-81+20 = -83

8 0
3 years ago
Please help me with this question. Algebra 2 is hard!!
trapecia [35]

Answer:

  • domain: {x ∈ ℝ : x ≤ 5}
  • range: {y ∈ ℝ : y ≤ -1}

Step-by-step explanation:

<u>Domain</u>

The domain of a function is the set of x values for which the function is defined. Here, the domain is limited by the values of x that make the square root defined. That is, the expression under the radical cannot be negative:

  -3x +15 ≥ 0

  15 ≥ 3x . . . . . . add 3x

  5 ≥ x . . . . . . . . divide by 3

  x ≤ 5 . . . . . . . . put x on the left (swap sides)

The rest of the notation in the domain expression simply says x is a real number.

  domain: {x ∈ ℝ : x ≤ 5} . . . . . . matches the first choice

__

<u>Range</u>

The range of a function is the set of values that f(x) can have. We know the square root can be zero or any positive number. When it is zero, f(x) = -1.

When it is a positive number, that value is multiplied by -4 and added to -1, so f(x) is a number more negative than -1. Then the range of the function is all numbers -1 and below:

  range: {y ∈ ℝ : y ≤ -1} . . . . . . matches the last choice

_____

<em>Comment on domain/range problems</em>

When working domain and range problems, it works well to have a good understanding of the domain and range limitations of the functions we usually work with: polynomials, square root, logarithm, trig functions, exponential functions. Domain and range problems generally involve combinations of these or ratios of combinations of these.

3 0
3 years ago
Find all solutions of the equation in the interval [0,2pi)
irinina [24]

Answer:

{π/4, 5π/4}

Step-by-step explanation:

Tan theta -1=0 could be rewritten as tan Ф = 1.  The tangent function is 1 at Ф = π/4.  As the period of the tangent function is π,

tan Ф = 1 will be true for Ф = π/4 + π, or (5/4)π.

The solution set is {π/4, 5π/4}.

4 0
3 years ago
Find the surface area of a cylinder with a base diameter of 8ft and a height of 6ft. Write your answer in terms of pi, and be su
Ksju [112]

Given that diameter of the base of the cylinder = 8 ft

Given that height of the cylinder = 6 ft

We have to find the surface area of the cylinder in terms of pi.

So we need to use formula of surface area of the cylinder which is

Area= 2\pi r(r+h)

where h= height = 6

r= radius = diameter/2 = 8/2 = 4

Now plug these values into above formula

Area= 2\pi *4(4+3)

Area= 2\pi *4(7)

Area= 2\pi *28

Area= 56\pi

Hence final answer is

Area= 56\pi square ft

3 0
3 years ago
Read 2 more answers
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