Explain -2y+6=-12 thank u

For which of the following graphs would it NOT make sense to connect

marshall27 [118]

Answer:

B

Step-by-step explanation:

the rest of the answers are the same and it is harder to compare if the lines are connected because you are most likely going to use a bar graph

6 0

3 years ago

If WXY is equilateral and WZY is<br> isosceles, find each missing measure.

timurjin [86]

Answer:

m∠1 = 60°

m∠2 = m∠4 = 39°

m∠3 = m∠5 = 21°

Step-by-step explanation:

ΔWXY is a equilateral angle,

Therefore, all angles of the the triangle are equal in measure.

m∠W + m∠X + m∠Y = 180°

3m∠W = 180°

m∠W = 60°

Since, ΔWZY is an isosceles triangle,

m∠3 = m∠5

m∠3 + m∠Z + m∠5 = 180°

m∠3 + 138° + m∠3 = 180°

2m∠3 = 180 - 138

m∠3 = 21°

Therefore, m∠3 = m∠5 = 21°

Since, m∠2 + m∠3 = 60°

m∠2 = 60 - 21

= 39°

Since, m∠4 + m∠5 = 60°

m∠4 = 60 - 21

= 39°

m∠1 = 60°

7 0

2 years ago

Read 2 more answers

A study of the number of business lunches that executives in the insurance and banking industries claim as deductible expenses p

gizmo_the_mogwai [7]

Answer:

$t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604$

$p_v =2*P(t_{(88)}>2.604)=0.0108$

So the p value is a very low value and using any significance level for given $\alpha=0.05$ always $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

Step-by-step explanation:

Data given and notation

$\bar X_{1}=9.1$ represent the mean for the sample 1

$\bar X_{2}=8$ represent the mean for the sample 2

$s_{1}=1.9$ represent the sample standard deviation for the sample 1

$s_{2}=2.1$ represent the sample standard deviation for the sample 2

$n_{1}=40$ sample size for the group 1

$n_{2}=50$ sample size for the group 2

t would represent the statistic (variable of interest)

Concepts and formulas to use

We need to conduct a hypothesis in order to check if the mean are different , the system of hypothesis would be:

Null hypothesis: $\mu_{1} = \mu_{2}$

Alternative hypothesis: $\mu_{1} \neq \mu_{2}$

If we analyze the size for the samples both are higher than 30 and the population deviations are not given, so for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Calculate the statistic

We can replace in formula (1) the results obtained like this:

$t=\frac{9.1-8}{\sqrt{\frac{(1.9)^2}{40}+\frac{(2.1)^2}{50}}}}=2.604$

Statistical decision

The first step is calculate the degrees of freedom, on this case:

$df=n_{1}+n_{2}-2=40+50-2=88$

Since is a bilateral test the p value would be:

$p_v =2*P(t_{(88)}>2.604)=0.0108$

So the p value is a very low value and using any significance level for given $\alpha=0.05$ always $p_v$ so we can conclude that we have enough evidence to reject the null hypothesis, and there is enough evidence to conclude that the two means are significantly different at 5%

3 0

3 years ago

Find the difference between ( x+ 5) and (2x+3)

Lynna [10]

The first one = 5 and the second one = -6
hope this helps

4 0

3 years ago

A parking lot has seventy-six parking spaces numbered from 1 to 76. There are no cars in the parking lot when Jillian pulls in a

Elodia [21]

Answer:

40/76 or 10/19 or 52.63% (they are all equivalent)

Step-by-step explanation:

there are 76 parking spaces in total

30 parking spaces have numbers that are less than 31 (1 - 30)

that means that there are 76 - 30 = 46 spaces that are numbered 31 or higher

so the probability that Jillian parks on a parking space with a number ≥ 31 is 40/76 or 10/19 or 52.63%

8 0

2 years ago