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Explanation:
Here is one way to go about it.
<u>Statement</u> . . . . <u>Reason</u>
1. AD ≅ BC, AD║BC, E & F are midpoints of BC, AD . . . . given
2. (1/2)AD ≅ (1/2)BC . . . . multiplicative property of congruence (equality)
3. DF = (1/2)AD, BE = (1/2)BC . . . . definition of midpoint
4. DF ≅ BE . . . . substitution property of congruence
5. BE║DF . . . . segments of parallel lines are parallel
6. BEDF is a parallelogram . . . . BE ≅ DF, BE║DF, definition of parallelogram
