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3 years ago

10

Find the median of 38,37,39,41,38,42,48,50,54

1 answer:

zhuklara [117]3 years ago

8 0

Median = 41

hope that helps

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PLEASE HELP ME SHAWTIES PRESS ON IMAGE

irina1246 [14]

Answer:

Where's the image?

Step-by-step explanation:

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3 years ago

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Caroline scored 8 more points than three times the number of points as Kamila. If Kamila scores 8 points in her next try, she wi

nlexa [21]

Answer: 32

step by step explanation: 40 - 8 = 32

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2 years ago

What two decimals are equivalent to 4.400

Zina [86]

Answer:

4.4

4.40

Step-by-step explanation:

These two decimals above are equivalent to 4.400 because no matter the amount of zeroes, the numbers are the same. For example, 4.400 is also equivalent to 4.400000000000000000000000000000000. As long as the "4's" maintain the same place (ones place and tens place), the decimals will be congruent to one another.

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4 years ago

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Of the 180 students in Mrs. Stanfield's class,

Nesterboy [21]

Answer:

should be 27

Step-by-step explanation:

60% of 180 is 108

25% of 108 is 27

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3 years ago

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The U.S. and many other countries have recently tightened airport security. A sociologist is interested in estimating the propor

melisa1 [442]

Answer:

0.0073 < 0.05, which means that we reject the null hypothesis and conclude that the true proportion of interest is higher than 0.7.

Step-by-step explanation:

Conduct a test to determine whether the true proportion of interest is higher than 0.7.

This means that the null hypothesis is: $H_{0}: p = 0.7$

And the alternate hypothesis is: $H_{a}: p > 0.7$

The test statistic is:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

In which X is the sample mean, $\mu$ is the value tested at the null hypothesis, $\sigma$ is the standard deviation and n is the size of the sample.

0.7 is tested at the null hypothesis:

This means that $\mu = 0.7, \sigma = \sqrt{0.7*0.3}$

The sociologist found that 375 of the 500 travelers randomly selected and interviewed indicated that the airports were safe.

This means that $n = 500, X = \frac{375}{500} = 0.75$

Value of the z-statistic:

$z = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{0.75 - 0.7}{\frac{\sqrt{0.7*0.3}}{\sqrt{350}}}$

$z = 2.44$

P-value of the test:

Probability of z being larger than 2.44, that is, a proportion larger than 0.75.

This is, looking at the z-table, 1 subtracted by the pvalue of Z = 2.44. S

Z = 2.44 has a pvalue of 0.9927

1 - 0.9927 = 0.0073

0.0073 < 0.05, which means that we reject the null hypothesis and conclude that the true proportion of interest is higher than 0.7.

8 0

3 years ago