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gladu [14]
3 years ago
12

What is the slope of a line perpendicular to the line y = −14x – 1?

Mathematics
1 answer:
mash [69]3 years ago
5 0

Answer:

<h2>         m = ¹/₁₄</h2>

Step-by-step explanation:

y=m₁x+b₁   ⊥   y=m₂x+b₂   ⇔    m₁×m₂ = -1

{Two lines are perpendicular if the product of theirs slopes is equal -1}

y = -14x - 1   ⇒   m₁ = -14

-14×m₂ = -1        ⇒    m₂ = ¹/₁₄

So, the slope of a line perpendicular to the line y = -14x - 1 is m = ¹/₁₄

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Need help solving this problem ​
natka813 [3]

Answer:

Part 1: \frac{11-x}{5} or \frac{11}{5}-\frac{x}{5}

Part 2: \frac{9}{5}

Step-by-step explanation:

To start things off, you must put everything on the opposite side of y so that you only have the y variable left.

In this case, put x onto the other side, making it negative since it's flipped, so you get 5y=11-x (since the x is negative you're using subtraction from 11).

Next, divide both sides by 5 to make 5y into y:

\frac{5y}{5} =\frac{11}{5}-\frac{x}{5}

y=\frac{11}{5}-\frac{x}{5}

Then in this case you turn y=f(x), but the system did it for you, so all you have to put is \frac{11}{5}-\frac{x}{5}.

For the second part you must replace x with 2 since you need to find f(2).

\frac{11-2}{5}

Your answer for part 2 is \frac{9}{5}.

3 0
2 years ago
The product of 2 and a number increased by 7 is -36
Sholpan [36]
"The product" means you're multiplying the two numbers.
"a number" refers to a variable.
"increased" means you're adding.

2x + 7 = -36
3 0
3 years ago
In 1980, the median age of the U.S. population was 30.0; in 2000, the median age was 35.3.
miss Akunina [59]

Answer:

y = 0.265x - 494.7

Step-by-step explanation:

Let median age be represent by 'a' and time be represent by 't'

In 1980, median age is given 30

which means that

a₁ = 30

t₁ = 1980

In 2000, the median age is given 35.3

which means that.

a₂ = 35.3

t₂ = 2000

The slope 'm' of the linear equation can be found by:

m = (a₂ - a₁) /(t₂ - t₁)

m = (35.3 - 30)/(2000-1980)

m = 0.265

General form of linear equation is given by:

y = mx + c

y = 0.265x +c

Substitute point (1980,30) in the equation.

30 = 0.265(1980) + c

c = -494.7

Hence the the linear equation can be written as:

y = mx + c

y = 0.265x - 494.7

4 0
3 years ago
The following stem-and-lead plot shows the One record attendance for original Charity Drive meetings what is the mode of these v
Gala2k [10]

Answer:

CHOOSE  A. 48

Step-by-step explanation:

Because its easy just do it.

8 0
3 years ago
Further mathematics: Find the derivative of the function x^2 y + (xy)^3 +3x=0 at (-1 , 3)​
vesna_86 [32]

Answer:

3.

Step-by-step explanation:

Implicit differentiation:

x^2 y + (xy)^3 + 3x = 0

x^2 y + x^3y^3 + 3x = 0

Using the product rule:

2x* y + x^2*dy/dx + 3x^2 y^3 + x^3* (d(y^3)/dx) + 3 = 0

2xy + x^2 dy/dx + 3x^2 y^3 + x^3* 3y^2 dy/dx + 3 = 0

dy/dx(x^2 + 3y^2x^3) =  (-2xy - 3x^2y^3 - 3)

dy/dx=  (-2xy - 3x^2y^3 - 3) / (x^2 + 3y^2x^3)

At the point (-1, 3).

the derivative =  (6 - 81 - 3)/(1 -27)

= -78/-26

=  3.

8 0
2 years ago
Read 2 more answers
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