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UNO [17]
3 years ago
12

It is commonly assumed that babies are equally likely to come as either a boy or a girl. This is not true. Actually, about 51.3%

of all babies are boys. If a family has two children (not twins), what is the chance both children are boys
Mathematics
1 answer:
Brums [2.3K]3 years ago
3 0

Answer: 0.263169

Step-by-step explanation:

Since for every child there is two outcomes (either a boy or a girl), so it is a binomial distribution.

Let x = Number of boys

Given: probability that a child is a boy: p= 0.513

Binomial distribution formula : P(X=x)=^nC_xp^x(1-p)^{n-x}

Now, the probability that  both children are boys= P(X=2)=^2C_2(0.513)^2(1-0.513)^0

=(1)(0.513)^2(1)\\\\=0.263169

The chance both children are boys = 0.263169

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The dimensions of the garden that minimize the cost is 9.018 feet(length) and 13.528 feet(width)

Step-by-step explanation:

Let the length of garden be x

Let the breadth of garden be y

Area of Rectangular garden = Length \times Breadth = xy

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So, xy=122 ---A

A landscape architect wished to enclose a rectangular garden on one side by a brick wall costing $20/ft

So, cost of brick along length x = 20 x

On the other three sides by a metal fence costing $10/ft.

So, Other three side s = x+2y

So, cost of brick along the other three sides= 10(x+2y)

So, Total cost = 20x+10(x+2y)=20x+10x+20y=30x+20y

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f(x)=\frac{2440}{x}+30x

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Now check whether it is minimum or not

take second derivative

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Substitute the value of x

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f''(x)=6.6540

Since it is positive ,So the x is minimum

Now find y

Substitute the value of x in A

(9.018)y=122

y=\frac{122}{9.018}

y=13.528

Hence the dimensions of the garden that minimize the cost is 9.018 feet(length) and 13.528 feet(width)

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