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Sergeeva-Olga [200]
2 years ago
12

What is 8x-7(x+3)+5x

Mathematics
2 answers:
jek_recluse [69]2 years ago
5 0

Answer:

6x-21

Step-by-step explanation:

First distribute

8x-7(x+3)+5x

8x-7x-21+5x

Then combine like terms

8x-7x-21+5x

6x-21

OLga [1]2 years ago
4 0

Answer:

I'm not 100% sure love, but I think it would be 12x.

Step-by-step explanation:

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Step-by-step explanation:

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2 years ago
What is the solution to he equation (y/y-4)-(4/y+4)=3^2/y^2-16
kicyunya [14]

Answer:

y=\pm i \sqrt{7}

Step-by-step explanation:

Given equation is \frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}

Factor denominators then solve by making denominators equal

\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{3^2}{(y^2-16)}

\frac{y}{\left(y-4\right)}-\frac{4}{\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}

\frac{y\left(y+4\right)-4\left(y-4\right)}{\left(y-4\right)\left(y+4\right)}=\frac{9}{(y+4)\left(y-4\right)}

y\left(y+4\right)-4\left(y-4\right)=9

y^2+4y-4y+16=9

y^2=9-16

y^2=-7

take squar root of both sides

y=\pm \sqrt{-7}

y=\pm i \sqrt{7}

Hence final answer is y=\pm i \sqrt{7}.

7 0
3 years ago
the area of a rectangular volleyball court is 1800 square feet the courts length is twice it width write a system of equations t
Marianna [84]

Answer:

The dimensions of the rectangular volleyball court are 60 ft x 30 ft

Step-by-step explanation:

Let

x ----> the length of rectangular volleyball court

y ---> the width of the rectangular volleyball court

we know that

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so

1,800=xy ----> equation A

x=2y -----> equation B

substitute equation B in equation A

1,800=(2y)y

1,800=2y^2

Solve for y

Simplify

900=y^2

take square root both sides

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x=2y

substitute the value of y

x=2(30)=60\ ft

therefore

The dimensions of the rectangular volleyball court are 60 ft x 30 ft

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3 years ago
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Answer is <span>d. 3 + 2 = 5 and 50 ÷ 5 = 10

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