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velikii [3]
3 years ago
7

WORTH 20 POINTS ✨HELPPP PLEASEEE

Mathematics
1 answer:
nekit [7.7K]3 years ago
4 0

Answer: 9.42 for circumference and the area is 7.065

Step-by-step explanation:

You might be interested in
The curve
kherson [118]

Answer:

Point N(4, 1)

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right  

Equality Properties

  • Multiplication Property of Equality
  • Division Property of Equality
  • Addition Property of Equality
  • Subtraction Property of Equality<u> </u>

<u>Algebra I</u>

  • Coordinates (x, y)
  • Functions
  • Function Notation
  • Terms/Coefficients
  • Anything to the 0th power is 1
  • Exponential Rule [Rewrite]:                                                                              \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Rule [Root Rewrite]:                                                                     \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}

<u>Calculus</u>

Derivatives

Derivative Notation

Derivative of a constant is 0

Basic Power Rule:

  • f(x) = cxⁿ
  • f’(x) = c·nxⁿ⁻¹

Derivative Rule [Chain Rule]:                                                                                    \displaystyle \frac{d}{dx}[f(g(x))] =f'(g(x)) \cdot g'(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle y = \sqrt{x - 3}<u />

<u />\displaystyle y' = \frac{1}{2}<u />

<u />

<u>Step 2: Differentiate</u>

  1. [Function] Rewrite [Exponential Rule - Root Rewrite]:                                   \displaystyle y = (x - 3)^{\frac{1}{2}}
  2. Chain Rule:                                                                                                        \displaystyle y' = \frac{d}{dx}[(x - 3)^{\frac{1}{2}}] \cdot \frac{d}{dx}[x - 3]
  3. Basic Power Rule:                                                                                             \displaystyle y' = \frac{1}{2}(x - 3)^{\frac{1}{2} - 1} \cdot (1 \cdot x^{1 - 1} - 0)
  4. Simplify:                                                                                                             \displaystyle y' = \frac{1}{2}(x - 3)^{-\frac{1}{2}} \cdot 1
  5. Multiply:                                                                                                             \displaystyle y' = \frac{1}{2}(x - 3)^{-\frac{1}{2}}
  6. [Derivative] Rewrite [Exponential Rule - Rewrite]:                                          \displaystyle y' = \frac{1}{2(x - 3)^{\frac{1}{2}}}
  7. [Derivative] Rewrite [Exponential Rule - Root Rewrite]:                                 \displaystyle y' = \frac{1}{2\sqrt{x - 3}}

<u>Step 3: Solve</u>

<em>Find coordinates</em>

<em />

<em>x-coordinate</em>

  1. Substitute in <em>y'</em> [Derivative]:                                                                             \displaystyle \frac{1}{2} = \frac{1}{2\sqrt{x - 3}}
  2. [Multiplication Property of Equality] Multiply 2 on both sides:                      \displaystyle 1 = \frac{1}{\sqrt{x - 3}}
  3. [Multiplication Property of Equality] Multiply √(x - 3) on both sides:            \displaystyle \sqrt{x - 3} = 1
  4. [Equality Property] Square both sides:                                                           \displaystyle x - 3 = 1
  5. [Addition Property of Equality] Add 3 on both sides:                                    \displaystyle x = 4

<em>y-coordinate</em>

  1. Substitute in <em>x</em> [Function]:                                                                                \displaystyle y = \sqrt{4 - 3}
  2. [√Radical] Subtract:                                                                                          \displaystyle y = \sqrt{1}
  3. [√Radical] Evaluate:                                                                                         \displaystyle y = 1

∴ Coordinates of Point N is (4, 1).

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Derivatives

Book: College Calculus 10e

4 0
3 years ago
Nico can do 42 push-ups in 3 minutes.
Alchen [17]

Step-by-step explanation:

Hey there!

It is said we need to find the unit rate.

What we can do is apply Unitary Method.

3 minutes = 42 push ups

1 minute = \sf{\bf{\dfrac{42}{3}}}

<u>So, 12 push ups per minute is the unit rate.</u>

In 5 minutes, he will do 12×5 = <u>60 push ups!</u>

Hope it helps :)

4 0
3 years ago
Will Mark Brainliest!!! Which statement represents the simplified form of the given equation and correctly describes the solutio
Iteru [2.4K]

The statement 14 \neq 15 no solutions represents the simplified form of the given equation 6x + 14 = 3(2x + 5). Hence Option A is correct

<u>Solution:</u>

Given, equation is 6x + 14 = 3(2x + 5).

We have to find the correct options that represents the simplified form of the given equation and correctly describes the solution.

So, now let us simplify the given equation  

⇒6x + 14 = 3(2x + 5) ⇒ 6x + 14 = 6x + 15 ⇒ 6x – 6x + 14 = 15 ⇒ 14 ≠ 15

As L.H.S not equals with R.H.S, no value of x can satisfy the equation and there will be no solution for given equation.

Hence, option A is correct.  

4 0
3 years ago
Which is an estimate of square root of 15 to one decimal place?
Wewaii [24]
3.9 is the estimated square root of 15 to one decimal place
8 0
3 years ago
Read 2 more answers
How many kilometers did they drive per hour
Elza [17]
The distance from San Francisco to New York is 4140 km. Since the question asks how long it took the Humphrey family in km/hr (kilometers per hour), you would just divide 4140km by 6.
Why? Because it took them 6 hours to make a trip of 4140 km. Dividing 4140 by 6 gives you the distance they traveled per hour.

690 km/hr
3 0
4 years ago
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