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2 years ago

The side lengths of a triangle are 7, 24, and 25. Is this triangle a right triangle?

Mathematics

2 answers:

nordsb [41]2 years ago

6 0

Yes. Hope this helps :)

IrinaVladis [17]2 years ago

4 0

Answer:

yes

Step-by-step explanation:

for it to be a right triangle you should be able to add two of the sides and it be greater than the third side. 7 + 24 > 25

24 + 25 > 7

7 + 25 > 24 therefore it is indeed a right triangle

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Which logarithmic equation is equivalent to the exponential equation below?

aleksandr82 [10.1K]

Option B: $\ln 6=5 x$ is the correct answer.

Explanation:

The exponential equation is $e^{5 x}=6$

If $f(x)=g(x)$ , then $\ln (f(x))=\ln (g(x))$

Thus, the equation becomes

$\ln \left(e^{5 x}\right)=\ln (6)$

Applying log rule, $\log _{a}\left(x^{b}\right)=b \cdot \log _{a}(x)$ and thus the equation becomes

$5 x \ln (e)=\ln (6)$

Since, we know that, $\ln (e)=1$ , using this we get,

$5 x=\ln (6)$

Hence, the logarithmic equation which is equivalent to the exponential equation $e^{5 x}=6$ is $\ln 6=5 x$

Thus, Option B is the correct answer.

7 0

2 years ago

Shelly Ann Fraser Pryce ran the 100m in 10.7 seconds. If she runs at a constant pace, how long will it take her to run 1/2 Km?

kvv77 [185]

Answer:53.5 Seconds ;)

3 0

2 years ago

Q6. The diagram shows two similar solids, A and B.

solniwko [45]

Answer:

640cm³

Step-by-step explanation:

Length SF = ×2

Volume SF = ×2³ = ×8

Volume of B = 8 × 80 = 640cm³

6 0

2 years ago

A total of 1 232 students have taken a course in Spanish, 879 have taken a course in French, and 114 have taken a course in Russ

ElenaW [278]

Answer:

$n(S\cap F \cap R)=7$

Step-by-step explanation:

The Universal Set, n(U)=2092

$n(S)=1232\\n(F)=879\\n(R)=114$

$n(S\cap R)=23\\n(S\cap F)=103\\n(F\cap R)=14$

Let the number who take all three subjects, $n(S\cap F \cap R)=x$

Note that in the Venn Diagram, we have subtracted $n(S\cap F \cap R)=x$ from each of the intersection of two sets.

The next step is to determine the number of students who study only each of the courses.

$n(S\:only)=1232-[103-x+x+23-x]=1106+x\\n(F\: only)=879-[103-x+x+14-x]=762+x\\n(R\:only)=114-[23-x+x+14-x]=77+x$

These values are substituted in the second Venn diagram

Adding up all the values

2092=[1106+x]+[103-x]+x+[23-x]+[762+x]+[14-x]+[77+x]

2092=2085+x

x=2092-2085

x=7

The number of students who have taken courses in all three subjects, $n(S\cap F \cap R)=7$

3 0

2 years ago

Solve: A = 4pir2 for r.

Airida [17]

<span>r means radius so it can't be negative.

<=>

A = 4 pi r²

r = sqr (A / 4pi)
</span>

5 0

2 years ago