In short, (h o g)(a) is just h( g(a) ).
so what we can do is simply get g(a) first and then plug that in h(x).
so what we can do is simply get g(a) first and then plug that in h(x).
two mechanics worked on a car. the first mechanic worked for 5 hours, and the second mechanic worked for 15 hours. Together they
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<h2>30.67 pounds of 32% copper alloy and 10.33 pounds of 65% copper alloy</h2>Step-by-step explanation:
First alloy contains 32% copper and the second alloy contains 65% alloy.
We wish to make 44 pounds of a third alloy containing 42% copper.
Let the weight of first alloy used be in pounds and the weight of second alloy used be
in pounds.
Total weight =
Total weight of copper =
Subtracting 32 times first equation from second equation,
∴ 30.67 pounds of first alloy and 13.33 pounds of second alloy were used.