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Mademuasel [1]
3 years ago
13

South school has 750 students. North school has 13/15 times as many students as South

Mathematics
1 answer:
puteri [66]3 years ago
5 0

Answer:

fewer

Step-by-step explanation:

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I need help on this how do i do this
kap26 [50]
Answer: 4311/9900 = 0.4354 4936/990 = 4.985 530/900 = 0.58 674/990 = 0.680 8099/990 = 8.180 explanation: divide the numbers and select the answers.
7 0
2 years ago
Which is equivalent to sqrt x^10<br> A. X-5<br> B. X -1/5<br> C. X sqrt 10<br> D. X 1/5<br> E. X^5
Lesechka [4]
<h3>Answer:  E) x^5</h3>

\sqrt{x^{10}} = x^5

=====================================================

Explanation:

We simply take half of the exponent 10 to get 5. This applies to square roots only.

So the rule is \sqrt{a^b} = a^{b/2}

A more general rule is

\sqrt[n]{a^b} = a^{b/n}

If n = 2, then we're dealing with square roots like with this problem. In this case, a = x and b = 10.

5 0
3 years ago
Read 2 more answers
Pleaseeee help ASAP it’s due today :(
Aleksandr [31]

Let, price increased by x times.

New price = 40 + ( 1 × x ) = 40 + x

It is given that for each $1 increase park loses 300 visitors.

Number of visitors = ( 24000 - 300x )

So, revenue is given by :

R = ( 24000 - 300x )( 40 + x )    ....1)

To finding critical point :

R'(x) = 0

-300( 40 + x )  + ( 24000 - 300x ) = 0     .....By product law

-12000 - 300x + 24000 -300x = 0

600x = 12000

x = 20

So, revenue is maximum at x = 20 .

Putting x = 20 in equation 1) , we get :

R = ( 24000 - 300x )( 40 + x )

R = [ 24000 - 300(20)][40 + 20 ]

R = $1080000

Therefore, park should charge $( 40 + 20 ) = $60 for maximising the revenue and maximum revenue is  $10,80,000  .

Hence, this is the required solution.

5 0
3 years ago
The triangle and the rectangle below have the same area.
Setler [38]

Answer:

<h2>look at the photo...........................</h2>

7 0
3 years ago
Multiply: (x+4)(x^2+2x+3) <br> Simplify and write your answer in Standard Form.
Oxana [17]

Answer:

x^3+6x^2+11x+12

Step-by-step explanation:

(x+4)(x^2+2x+3)

=x(x^2+2x+3)+4(x^2+2x+3) [by multiplying with bith sides]

=x^3+2x^2+3x+4x^2+8x+12

=x^3+2x^2+4x^2+3x+8x+12

=x^3+6x^2+11x+12

(please mark me brainliest)

6 0
2 years ago
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