Answer:
.
Step-by-step explanation:
Considering the conversion from exponent to radical, the equation that justifies why the expression ![9^{\frac{1}{3}} = \sqrt[3]{9}](https://tex.z-dn.net/?f=9%5E%7B%5Cfrac%7B1%7D%7B3%7D%7D%20%3D%20%5Csqrt%5B3%5D%7B9%7D)
is correct is.
<h3>How is the conversion from exponent to radical realized?</h3>
The conversion of rational exponents to radical notation is modeled by:
![a^{\frac{n}{m}} = \sqrt[m]{a^n}](https://tex.z-dn.net/?f=a%5E%7B%5Cfrac%7Bn%7D%7Bm%7D%7D%20%3D%20%5Csqrt%5Bm%5D%7Ba%5En%7D)
In this problem, the expression is:
And the equation that shows that this is correct is:
More can be learned about the conversion from exponent to radical at brainly.com/question/19627260
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Answer:
g(x) = x+1
Step-by-step explanation:
Informally, you can see that the function h(x) takes the root of a value that is 1 more than the value under the same radical in f(x). This suggests that adding 1 to x in f(x) will give you h(x). That is, ...
h(x) = f(x+1) = f(g(x))
so
g(x) = x+1
_____
More formally, you can apply the inverse of the function f(x) to the equation ...
h(x) = f(g(x))
f^-1(h(x)) = f^-1(f(g(x))) . . . inverse function applied
f^-1(h(x)) = g(x) . . . . . . . . . simplified
Now f^-1(x) can be found by solving for y in ...
x = f(y)
x = ∛(y+2) . . . . . . . . . definition of f(y)
x^3 = y+2 . . . . . . . . . cube both sides
x^3 -2 = y = f^-1(x) . . . subtract 2 from both sides
So, f^-1(h(x)) is ...
f^-1(h(x)) = g(x) = (∛(x+3))^3 -2 = x+3 -2
g(x) = x+1
0.4 is four tenths. 0.4 = 4/10=2/5
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