Nine different numbers between 10 and 200 that have a sum of their digits equal.to 6
1 answer:
One answer (of several) would be 33: It's between 10 and 200 and the sum of its digits is 6. Continue this same pattern to identify other answers.
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C = 2πr
C = 2(3.14)(0.8)
C = 2(2.512)
C = 5.024 m
The answer is C.
Answer:
-11.8
Step-by-step explanation:
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D
Step-by-step explanation:
11 per 1,000
Answer:
5) 2(4 - n) = -3n
2 × 4 - 2 × n = -3n
8 - 2n = -3n
-2n + 3n = -8
1n = -8
n = -8/1
n = -8
6) 5 - 3(2 + 2w) = -7
5 - 3 × 2 + -3 × 2w = -7
5 - 6 - 6w = -7
-1 - 6w = -7
-6w = -7 + 1
-6w = -6
w = -6/-6
w = 1
7) 5(2r + 3) - 5 = 0
5 × 2r + 5 × 3 - 5 = 0
10r + 15 - 5 = 0
10r + 10 = 0
10r = -10
r = -10/10
r = -1
8) 3 - 5(2d - 3) = 4
3 - 5 × 2d - 5 × -3 = 4
3 - 10d + 15 = 4
-10d + 15 + 3 = 4
-10d + 18 = 4
-10d = 4 - 18
-10d = -14
d = -14/-10
d = 7/5
hope this helps you!!