Answer:
y=6/5x-2
Step-by-step explanation:
y=mx+C
Y=6/5X+C
4=6+c
c=-2
y=6/5x-2
D. Subtract 2 from the number of sides and multiply the difference by 180
Answer:
The area of the associated sector is
Step-by-step explanation:
step 1
Find the radius of the circle
we know that
The circumference of a circle is equal to

we have

substitute and solve for r


step 2
Find the area of the circle
we know that
The area of the circle is equal to

we have

substitute

step 3
Find the area of the associated sector
we know that
subtends the complete circle of area 
so
by proportion
Find the area of a sector with a central angle of 

55 is the estimated answer
Coefficients are the numbers in a equation variables are the letter