F = t ⇨ df = dt
dg = sec² 2t dt ⇨ g = (1/2) tan 2t
⇔
integral of t sec² 2t dt = (1/2) t tan 2t - (1/2) integral of tan 2t dt
u = 2t ⇨ du = 2 dt
As integral of tan u = - ln (cos (u)), you get :
integral of t sec² 2t dt = (1/4) ln (cos (u)) + (1/2) t tan 2t + constant
integral of t sec² 2t dt = (1/2) t tan 2t + (1/4) ln (cos (2t)) + constant
integral of t sec² 2t dt = (1/4) (2t tan 2t + ln (cos (2t))) + constant ⇦ answer
Answer:
I believe the numbers are 25 and 68.
Step-by-step explanation:
25 is the smaller number, 25 x 2 = 50, 50 + 18 = 68, and 68 + 25 = 93.
Answer:
you can't because they don't have common factors
Step-by-step explanation:
Hope this is what you are looking for the answer is 2(15-2n)
Either mean or median, they are both 14 in this data set.
