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lukranit [14]
3 years ago
14

HELP ME PLEASE!!!

Mathematics
1 answer:
Komok [63]3 years ago
6 0
Answer c, but then again i did this a while ago and my memory is cooky
You might be interested in
If 8a + 7b + c = 9, what is -6c - 48a - 42b
maksim [4K]

Answer:

-54

Step-by-step explanation:

8a + 7b + c = 9

We want -6c, but we have c in the equation so multiply by -6

-6(8a + 7b + c) = 9*-6

-48a -42b -6c = -54

Rearranging the equation

-6c - 48a - 42b = -54

6 0
3 years ago
Read 2 more answers
is it possible draw a right triangle with and obtuse angle? if so draw it in the box if not write impossible. is it possible guy
Ipatiy [6.2K]
It is not possible. Since one of the angles has to be a right angle, the other two angles would have to add to 90. Therefore, neither of these angles can be more than 90 degrees. 

Hope this helps
3 0
3 years ago
Find the y intercepts of 3x^2+24x-51. quadratic formula
julia-pushkina [17]
  • Quadratic Formula: x=\frac{-b\pm \sqrt{b^2-4ac}}{2a} , with a = x^2 coefficient, b = x coefficient, and c = constant.

Firstly, starting with the y-intercept. To find the y-intercept, set the x variable to zero and solve as such:

y=3*0^2+24*0-51\\y=0+0-51\\y=-51

<u>Your y-intercept is (0,-51).</u>

Next, using our equation plug the appropriate values into the quadratic formula:

x=\frac{-24\pm \sqrt{24^2-4*3*(-54)}}{2*3}

Next, solve the multiplications and exponent:

x=\frac{-24\pm \sqrt{576-(-648)}}{6}\\\\x=\frac{-24\pm \sqrt{576+648}}{6}

Next, solve the addition:

x=\frac{-24\pm \sqrt{1224}}{6}

Now, simplify the radical using the product rule of radicals as such:

  • Product Rule of Radicals: √ab = √a × √b

√1224 = √12 × √102 = √2 × √6 × √6 × √17 = 6 × √2 × √17 = 6√34

x=\frac{-24\pm 6\sqrt{34}}{6}

Next, divide:

x=-4\pm \sqrt{34}

<u>The exact values of your x-intercepts are (-4 + √34, 0) and (-4 - √34, 0).</u>

Now to find the approximate values, solve this twice: once with the + symbol and once with the - symbol:

x=-4+ \sqrt{34},-4- \sqrt{34}\\x\approx 1.83, -9.83

<u>The approximate values of your x-intercepts (rounded to the hundredths) are (1.83,0) and (-9.83,0).</u>

5 0
3 years ago
if pentagon abcd was reflected over the axis y-axis, reflected over the x-axis, and rotated 180, where would be point A' lie
frez [133]
A reflection over the x axis coupled with another reflection over the y axis leads to a rotation of 180 degrees. 

In other words,

Start with point A. Reflect over the x axis to get point B. Reflect B over the y axis to get point C. To go from A to C, we can rotate A 180 degrees about the origin.

----------------

So this means that if we do those reflections and then do the rotation, then we end up back where we started. Wherever point A is located, the point A' will also be located at the same position with the same coordinates. 
4 0
3 years ago
Show how you got y answers
trasher [3.6K]

Answer:

y = x - 3

Step-by-step explanation:

3x - 3y = 9

3x - 9 = 3y

x - 3 = y

y = x - 3

Then plug and chug for y by entering the given x values

3 0
3 years ago
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